RegEx split text string into dict as group

Question

I'm trying to RegEx string output and add into a dictionary as group of text and I'm using re.split() for that.

My string output is:

mpathag (36005076801b2014804000000000001cd) dm-7 Test ,2145
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw
|-+- policy='service-time 0' prio=50 status=active
| |- 12:0:1:3 sdas  66:192 active ready  running
| `- 13:0:1:3 sdbi  67:192 active ready  running
`-+- policy='service-time 0' prio=10 status=enabled
  |- 12:0:0:3 sdak  66:64  active ready  running
  `- 13:0:0:3 sdba  67:64  active ready  running
mpathz (36005076801b2014804000000000001c4) dm-0 Test ,2145
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw
|-+- policy='service-time 0' prio=50 status=active
| |- 12:0:0:0 sdah  66:16  active ready  running
| `- 13:0:0:0 sdax  67:16  active ready  running
 `-+- policy='service-time 0' prio=10 status=enabled
   |- 10:0:0:0 sdb   8:16   active ready  running
   `- 13:0:1:0 sdbf  67:144 active ready  running

Here my code of parsing:

    output = "mpathag (36005076801b2014804000000000001cd) dm-7 Test ,2145\
    size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw\
    |-+- policy='service-time 0' prio=50 status=active\
    | |- 12:0:1:3 sdas  66:192 active ready  running\
    | `- 13:0:1:3 sdbi  67:192 active ready  running\
    `-+- policy='service-time 0' prio=10 status=enabled\
      |- 12:0:0:3 sdak  66:64  active ready  running\
      `- 13:0:0:3 sdba  67:64  active ready  running\
    mpathz (36005076801b2014804000000000001c4) dm-0 Test ,2145\
    size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw\
    |-+- policy='service-time 0' prio=50 status=active\
    | |- 12:0:0:0 sdah  66:16  active ready  running\
    | `- 13:0:0:0 sdax  67:16  active ready  running\
     `-+- policy='service-time 0' prio=10 status=enabled\
       |- 10:0:0:0 sdb   8:16   active ready  running\
       `- 13:0:1:0 sdbf  67:144 active ready  running"

    devices = re.split('mpath', output)
    for dev in devices:
       print dev

My problem is that the re.split remove the pattern from the text it is possible split without removing the delimiter?

Output results are like that:

ag (36005076801b2014804000000000001cd) dm-7 Test ,2145    
size=488G features='1 queue_if_no_path' hwhandler='0' wp=rw    
|-+- policy='service-time 0' prio=50 status=active    
| |- 12:0:1:3 sdas  66:192 active ready  running    
| `- 13:0:1:3 sdbi  67:192 active ready  running    
`-+- policy='service-time 0' prio=10 status=enabled      
  |- 12:0:0:3 sdak  66:64  active ready  running      
  `- 13:0:0:3 sdba  67:64  active ready  running

How do you get the nicely formatted output when your string doesn't have any new line? — nhahtdh, Nov 18 '15 at 09:33

score 1 · Answer 1 · answered Nov 18 '15 at 09:55

If the pattern include capturing group, that group will not be excluded:

>>> re.split(',', '1,2,3')  # without capturing group
['1', '2', '3']
>>> re.split('(,)', '1,2,3')  # with capturing group
['1', ',', '2', ',', '3']
>>> xs = re.split('(,)', '1,2,3')
>>> [part1+part2 for part1, part2 in zip(xs[1::2], xs[2::2])]
[',2', ',3']

devices = re.split('(mpath)', output)
for part1, part2 in zip(devices[1::2], devices[2::2]):
    print part1 + part2

RegEx split text string into dict as group

1 Answers1