Builder pattern multiple varargs

Question

I'm reading up Joshua Bloch's 'Effective Java' where in Item 2, he mentions the advantages of using Builder pattern when dealing with several parameters in the constructor. All's good, until I saw the multiple var-args difference between the conventional constructor and this pattern. So, I have some doubts regarding it :

How does builder pattern allows for multiple var-args?
Why does a conventional constructor allows for only a single var-arg? (Maybe due to the fact that it'll cause ambiguity in case there are multiple var-args, when the defined data type for both is same, but I'm not sure this is the correct reason behind it.)

I haven't used var-args in my code though, but yes I know their use. Still I'm unable to understand the reason behind above statements. Any help would be appreciated.

score 7 · Accepted Answer · answered Nov 20 '15 at 07:58

7

No method signature (constructors included) allows for multiple varargs. There can be only one, and it has to be the last argument.

That is just a limitation in the language specification. And yes, the reason for that is likely that it can become ambiguous very fast if you allowed more flexibility.

In the builder pattern, there is no such limitation, as every parameter can get its own method.

  builder
    .withOptions("a", "b", "c")   // varargs
    .withColors("red", "blue")    // more varargs
    .build();

answered Nov 20 '15 at 07:58

Thilo

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could you share the code how would you write a builder pattern here – mitali Dec 04 '21 at 06:40
@mitali: That snippet above was supposed to be an example of the builder pattern. – Thilo Dec 04 '21 at 14:33

Builder pattern multiple varargs

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