How I can do to check if a string contains a comma with a space using a regular expression?

Question

The string contains a name, where the first part corresponds to the name and the second to the lastname.

The regular expression must verify these formats:

Invalid strings:

 "Surname1 Surname2 Name1 Name2" 
 "Surname1, Surname2, Name1 Name2"
 "Surname1 Surname2 Name1 Name2,"

I try the following: /([\w][\,][\s]{1}\b)/, but did not work

I appreciate any help.

Your regex works fine, just check if the match count is exactly equals 1 — Fedaykin, Nov 20 '15 at 18:46
Take a look here: http://stackoverflow.com/questions/1072765/count-number-of-matches-of-a-regex-in-javascript — Fedaykin, Nov 20 '15 at 19:37

score 1 · Answer 1 · answered Nov 20 '15 at 18:42

1

You can use this regex:

/\b\w+\s+\w+\s*,\s*\w+\s+\w+\b/

answered Nov 20 '15 at 18:42

anubhava

1

Thank you for your contribution, you helped me a lot. – Carlos Laspina Nov 20 '15 at 19:33

score 0 · Answer 2 · answered Nov 20 '15 at 18:55

If you want to support numbers in the name like your example above.

var validName = function (name) {
  return /^\w+ \w+, \w+ \w+$/.test(name);
};

or if any kind of whitespace is allowed between names

validName = function (name) {
  return /^\w+\s\w+,\s\w+\s\w+$/.test(name);
},

or if you only want to allow US letters

validName = function (name) {
  return /^[A-Za-z]+ [A-Za-z]+, [A-Za-z]+ [A-Za-z]+$/.test(name);
},

score 0 · Accepted Answer · answered Nov 20 '15 at 19:32

0

I found a solution that verifies both cases:

This is the regular expression: /\b\w+\s*\w*,\s\w+\s\w+\s*\w*\s*\w*\s*\w*\s*\w*$\b/

answered Nov 20 '15 at 19:32

Carlos Laspina

3 Answers3