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I am trying to test if a string is not equal to either of two strings. For example, in C++, this would be written as: 

if (string1 != string2 || string1 != string3)

However, attempting to create the Bash equivalent

if [ "$string1" != "$string2" || "$string1" != "$string3" ]

results in the error [: missing ']' and (contents of string1): command not found.

I'm not exactly too sure what is causing it, but searching didn't turn up any results I could use. It would be greatly appreciated if one could point out how the code I am using can be changed to suit the needs, and if possible, provide sample code.

Thanks in advance! Harry

perhapsmaybeharry
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1 Answers1

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At least three possibilities here:

if [ "$string1" != "$string2" ] || [ "$string1" != "$string3" ]

Or:

if [ "$string1" != "$string2" -o "$string1" != "$string3" ]

Or:

if [[ "$string1" != "$string2" || "$string1" != "$string3" ]]
julienc
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