Can call throw but it is not marked with try and the error is not handled

Asked Nov 25 '15 at 00:19

Active Nov 25 '15 at 00:33

Viewed 31 times

I am trying to run my Swift 1.0 syntax and am getting an error "Can call throw but it is not marked with try and the error is not handled.".

I tried adding a try / catch but a similar error occurs.

Here is the line of code:

        let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data!, options:NSJSONReadingOptions.MutableContainers) as? NSDictionary

I tried:

do {  
    let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data!, options:NSJSONReadingOptions.MutableContainers) as? NSDictionary  
} catch _ {  
    //Error handling, if needed  
}

but I get "Can throw but was not marked as try".

Please help

Also doesnt work when I try this:

edited Nov 25 '15 at 00:33

asked Nov 25 '15 at 00:19

dbus

You have to implement do try catch error handling – Leo Dabus Nov 25 '15 at 00:20
It says immutable value was never used. Then I cant access that variable further down. – dbus Nov 25 '15 at 00:33
Add the code related to your problem, the line and the error description – Leo Dabus Nov 25 '15 at 00:33
It should be `let jsonResult: NSDictionary! = try NSJSONSerialization.JSONObjectWithData(...` (you are missing the `try` keyword inside your `do` block). – Nicolas Miari Nov 25 '15 at 00:35
@dbus you have to pay attention at your variables life cycle. you can't have access to jsonResult further down (outside the brackets) – Leo Dabus Nov 25 '15 at 00:40
@dbus just create a dictionary property at your view controller class to store the jsonResult – Leo Dabus Nov 25 '15 at 00:42

Can call throw but it is not marked with try and the error is not handled

0 Answers0