If i input 1324,3591
It mean i want the bigger denote in order.
int x = 1324;
int y = 3591;
System.out.println(x+y);
I want the output show:
4321 and 8531
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kappa
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1Please show us some code you are trying. – Anton Samsonov Nov 26 '15 at 18:54
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Store them in an array, and sort them. – Am_I_Helpful Nov 26 '15 at 19:02
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can you get me an example : – kappa Nov 26 '15 at 19:10
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1How in the earth is this list `1234,1235,1589,1457,1489` be increasing ??? And `4321,5321,9851,7541,9841` be decreasing ?? – Jorge Campos Nov 26 '15 at 19:11
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i want the digits in order – kappa Nov 26 '15 at 19:13
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when i use this code, it was let the number in order: system.out.println("The decreasing order:"); for (int i = array.length - 1; i >= 0; i--) System.out.printf(array[i]); System.out.println(); – kappa Nov 26 '15 at 19:14
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So your INPUT is those ones not the output right ? Edit your question with your code – Jorge Campos Nov 26 '15 at 19:15
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1I think we all misunderstood you. We thought you wanted to have your *numbers* decreasing and increasing (i.e. the elements of the array in a specific order), but what you want is **per** number sort the digits, right? In your example, each array item is sorted, and not the array itself. – Bram Vanroy Nov 26 '15 at 19:28
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so how to do per number sort the digits – kappa Nov 26 '15 at 20:30
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@kappa I can show you the entire codes, but it seems that you don't really like to accept solutions. – user3437460 Nov 27 '15 at 08:25
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@user3437460 can you how me the entire codes – kappa Nov 27 '15 at 14:19
2 Answers
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Create two function, public int[] orderAsIncreasing(int input[]) and public int[] orderAsDecreasing(int input[]).
Then, loop inside the input searching for the highest value, and place it as the first/last in the output of each function. Remove that value from the array. Repeat until the array is empty. Then return the result
I will not post code, since this looks like some sort of homework. The logic is there. Now, use google and documentations to get the operators for it.
Bonatti
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but i use :Random r = new Random(); int x = r.nextInt(9999)+1; the input should be random number – kappa Nov 26 '15 at 19:19
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then change to what you need... `public int orderAsIncreasing(int input)`. Done. just `int s = orderAsIncreasing(r);` – Bonatti Nov 26 '15 at 19:27
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I think you should convert the numbers to strings and then to char arrays. If 'number' is your number, then something like:
String numberAsString = String.valueOf(number);
char[] charArray = numberAsString.toCharArray();
Arrays.sort(charArray);
String newNumberAsString = new String(charArray);
int number2= Integer.valueOf(newNumberAsString);
J Fabian Meier
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String numberAsString = String.valueOf(array); char[] charArray = numberAsString.toCharArray(); // in reverse order Arrays.sort(array); System.out.println(Arrays.asList()); System.out.println("The decreasing order:"); for (int i = array.length - 1; i >= 0; i--) System.out.printf(String.format("%04d ", numberAsString); System.out.println(); it can't run – kappa Nov 26 '15 at 20:29
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I have added some more code to make my point clear. If you need reverse order, you must sort with a different comparator. – J Fabian Meier Nov 27 '15 at 08:11
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if i want to being a decreasing order for 1325 out 5321 what should i do – kappa Nov 28 '15 at 18:45
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You have to implement your own comparator. See http://stackoverflow.com/questions/5393254/java-comparator-class-to-sort-arrays – J Fabian Meier Nov 30 '15 at 09:48