Why EOF doesn't terminate the program?

Question

#include<stdio.h>
int main()
{
    int a,b;
    char i;
   do{
        scanf("%d%d",&a,&b);
        printf("%d\n",b-a);
    }while(a!=EOF);
   return 0;
}

In this program when i press ctrl+z(EOF) it doesn't terminate.It print the last value and continue until I close the output console manually.What's the problem here?

but i take -1 two times to terminate.and i wanna do it with EOF.would you please tell me what's wrong with EOF? — Md Soman Khan, Nov 27 '15 at 06:18
http://stackoverflow.com/questions/1782080/what-is-eof-in-the-c-programming-language — Vishal Santharam, Nov 27 '15 at 06:32

score 0 · Answer 1 · answered Nov 27 '15 at 06:20

0

If you want to kill the program you have to press Control+C instead of Control+Z.

Here, The program iterates without stopping because it couldn't find a!=EOF condition. Because a is a address of memory location and the difference between those addresses never equals to EOF character. Therefore it iterates untill timeout.

answered Nov 27 '15 at 06:20

Darshana

130
1
8

But if I press Control+C it doesn't terminate from program but the output console will be closed. – Md Soman Khan Nov 27 '15 at 06:46
Ya. because it couldn't find a!=EOF condition. – Darshana Nov 30 '15 at 09:41

Why EOF doesn't terminate the program?

1 Answers1