why does my output is wrong in exponents in java

Question

why is it that this is wrong? i input the heightL as 2 the output must be 4 but there is something wrong

class He{
public static void main(String[] args)
{
    int heightL=2;
    int a = 9;
    System.out.println(Math.abs(a));
    System.out.println(2^(heightL));
}
}

why is it that the output in the second part is 0?

A fast way to do 2 to the power of is either `1L << x` for a long or `Math.scaleb(1, x)` for a double. — Peter Lawrey, Nov 30 '15 at 07:44

score 4 · Accepted Answer · answered Nov 30 '15 at 07:08

4

^ is not an exponent operator, it's bit-wise XOR (and 2 XOR 2 is 0).

For exponent, use Math.pow(2,heightL).

answered Nov 30 '15 at 07:08

Eran

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sir why is it possible loss of precision.? – Hello23 Nov 30 '15 at 07:13
@Hello23 Where do you see `possible loss of precision`? – Eran Nov 30 '15 at 07:15
thank you sir its already working.. – Hello23 Nov 30 '15 at 07:19

why does my output is wrong in exponents in java

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