How to get length of two dimensional array

Question

Create a two dimensional dynamic integer array S. The size should be seq1_length+1 and seq2_length+1. If seq1_length = 10 and seq2_length = 10answer should beS[11][11]`. I used this code

S= new int *[len1];
for(int i=0;i<len1;i++)
S[i]=new int[len2];

How can I check the size of this array supposed to be S[11][11].

duplicate of http://stackoverflow.com/questions/5508341/create-a-2d-array-with-variable-sized-dimensions — anukul, Nov 30 '15 at 15:21
The answer depends on what you want to do with it. You should say some words about the usage of the array. For an example, there are many matrix libraries out there for number crunching. — Tobias, Nov 30 '15 at 15:25

score 0 · Answer 1 · answered Nov 30 '15 at 19:29

First, you will get compile error "S does not name a type". Correct declaration should be

int* S = new int*[len1+1];
for (int i = 0; i < len1+1; i++)
{
    S[i] = new int[len2+1];
}

Len1+1 and Len2+1, because you need to have size one greater than seq1_length and seq2_length. For checking size you can simply do this

int count = 0;
for (int i = o; i < len1+1; i++)
{
    for (int j = o; j < len2+1; j++)
    {
        count++;
    }
}

std::cout << count << endl;

How to get length of two dimensional array

1 Answers1