Python: Alternate way to covert from base64 string to opencv

Question

I'm trying to convert this string in base64 (http://pastebin.com/uz4ta0RL) to something usable by OpenCV. Currently I am using this code (img_temp is the string) to use the OpenCV functions by converting it to a temp image(imagetosave.jpg) then loading the temp image with cv2.imread.

    fh = open('imagetosave.jpg','wb')
    fh.write(img_temp.decode('base64'))
    fh.close()

    img = cv2.imread('imagetosave.jpg',-1)

Though this method works, I would like to be able to use the OpenCV functions without using a temp image. Help would be much appreciated, thanks!

http://stackoverflow.com/a/33522724/5008845 – Miki Dec 01 '15 at 00:01 — Miki, Dec 01 '15 at 00:01
thanks, i thought i had already tried that but i guess not! – user3547372 Dec 01 '15 at 01:00 — user3547372, Dec 01 '15 at 01:00

score 0 · Answer 1 · answered Nov 30 '15 at 23:11

0

To convert string from base64 to normal you can use

import base64
base64.b64decode("TGlrZSB0aGF0Cg==")

but it itsn't unclear if is what you need.

answered Nov 30 '15 at 23:11

Nikita Sapozhnikov

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So I'd like to be able to use the string from base64 to a format useable by OpenCV without having to write over imagetosave.jpg since its acting as a temporary image. – user3547372 Nov 30 '15 at 23:14

score 0 · Answer 2 · answered Nov 30 '15 at 23:17

0

You can convert your decoded string to a list of integers, which you can then pass to the imdecode function:

img_array = map(int, img_temp.decode('base64'))
img = cv2.imdecode(img_array, -1)

answered Nov 30 '15 at 23:17

Sajjan Singh

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I'm getting: invalid literal for int() with base 10 – user3547372 Nov 30 '15 at 23:33

Python: Alternate way to covert from base64 string to opencv

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