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Following code give me undefined message.

var video = $('<video id="myVideo" width="320" height="176" controls>');
var source = $('<source>');
$(source).appendTo(video);
$(source).attr('src', 'php.mp4');
$(source).attr('type', 'video/mp4');
var d = $(video).duration;
console.log(d);
Anik Islam Abhi
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Roshan Patil
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0 Answers0