Executing unzip command programmatically

Question

I have created a shell script and inside of it is a simple statement unzip -o $1 and on running through terminal and passing a .zip file as parameter it works fine and takes 5 second to create unzipped folder.Now I am trying to do the same thing in scala and my code is as below :

object ZipExt extends App {

  val process = Runtime.getRuntime.exec(Array[String]("/home/administrator/test.sh", "/home/administrator/MyZipFile_0.8.6.3.zip"))
  process.waitFor

  println("done")
}

Now whenever I am trying to execute ZipExt it gets stuck in process.waitFor forever and print statement is not reached.I have tried using this code both locally and on server also. I tried other possibilites also like creating local variable inside shellscript, including exit statements inside shell script, trying to unzip other .zip other than mines, even sometimes print statement is executing but no unzipped file is created there. So I am pretty sure there is something wrong about executing unzip command programmatically to unzip a file or there is some other way around to unzip a zipped file programtically.I have been stuck with this problem for like 2 days, so somebody plz help..

score 1 · Accepted Answer · answered Dec 04 '15 at 15:11

The information you have given us appears to be insufficient to reproduce the problem:

% mkdir 34088099
% cd 34088099 
% mkdir junk
% touch junk/a junk/b junk/c
% zip -r junk.zip junk
updating: junk/ (stored 0%)
  adding: junk/a (stored 0%)
  adding: junk/b (stored 0%)
  adding: junk/c (stored 0%)
% rm -r junk
% echo 'unzip -o $1' > test.sh
% chmod +x test.sh
% scala
Welcome to Scala version 2.11.7 (Java HotSpot(TM) 64-Bit Server VM, Java 1.8.0_66).
Type in expressions to have them evaluated.
Type :help for more information.

scala> val process = Runtime.getRuntime.exec(Array[String]("./test.sh", "junk.zip"))
process: Process = java.lang.UNIXProcess@35432107

scala> process.waitFor
res0: Int = 0

scala> :quit
% ls junk 
a  b  c

I would suggest trying this same reproduction on your own machine. If it succeeds for you too, then start systematically reducing the differences between the succeeding case and the failing case, a step at a time. This will help narrow down what the possible causes are.

no instead of using `unzip` inside shell command I programatically now unzipped the `.zip` file — Aamir, Dec 07 '15 at 08:22
lol @Seth Tisue , check this out http://stackoverflow.com/questions/30640627/how-to-unzip-a-zip-file-using-scala — Aamir, Dec 08 '15 at 03:56

Executing unzip command programmatically

1 Answers1