List comprehension for first 10 alphabets

Question

I am trying to generate a list comprehension for first 10 letters.

letters = [l for l in 'a-j']
print(letters)

Output:

['a', '-', 'h']

This doesn't produce the expected output.How do I generate a list of first 10 alphabets?

`a-j` looks like a regex thing. Are you unhappy with `letters = [l for l in 'abcdefghij']`? — pushkin, Dec 05 '15 at 04:11
If you don't want a character range class, you could always hard-code it with `letters = list('abcdefghij')`. — TigerhawkT3, Dec 05 '15 at 04:12

score 8 · Answer 1 · answered Dec 05 '15 at 04:11

8

Use string.ascii_lowercase which contains the lowercase alphabets stored by default.

>>> import string
>>> string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'
>>> list(string.ascii_lowercase[:10])
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']

answered Dec 05 '15 at 04:11

Avinash Raj

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Because OP is trying to figure out how to get the chars between `a` and `j`, maybe `list(string.ascii_lowercase[string.ascii_lowercase.index('a'):string.ascii_l owercase.index('f')+1])` would be more clear? – Remi Guan Dec 05 '15 at 04:24

List comprehension for first 10 alphabets

1 Answers1