How to open android application if exists

Question

I would like to make android button and able to launch other application if already installed and go to S specified url if not yet installed.

Can you please explain your question properly? A bit more? – Dec 08 '15 at 10:07 — , Dec 08 '15 at 10:07

score 1 · Accepted Answer · answered Dec 08 '15 at 10:12

1

<a href="intent:#Intent;action=your.example.namespace.CUSTOMACTION;package=your.example.namespace;component=your.example.namespace/.activity.YourActivity;S.extraValueName=WOW;end">
Launch App

answered Dec 08 '15 at 10:12

PHP_RIDER

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score 0 · Answer 2 · answered Dec 08 '15 at 10:13

Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.name");
startActivity(launchIntent);

OR

Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("com.package.name","com.package.name.MainActivity"));
startActivity(intent);

score 0 · Answer 3 · edited May 23 '17 at 12:22

0

You can call specific application if you know the package name.

How do I programmatically launch a specific application in Android?

edited May 23 '17 at 12:22

Community

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answered Dec 08 '15 at 10:18

Anuj Sharma

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How to open android application if exists

3 Answers3