deleting items from dictionaries

Question

This is my dictionary

mydict = {'PENNY': 0, "NICKEL": 0, "DIME": 3, "QUARTER": 5, "HALF DOLLAR": 3, "ONE": 0}

It's a dictionary of the change I have in my pocket.

I want come up with way to delete the items from mydict whose values are 0.

I want to change

{'PENNY': 0, "NICKEL": 0, "DIME": 3, "QUARTER": 5, "HALF DOLLAR": 3, "ONE": 0}

into

{"DIME": 3, "QUARTER": 5, "HALF DOLLAR": 3}

How do I do this?

Welcome to Stack Overflow! You seem to be asking for someone to write some code for you. Stack Overflow is a question and answer site, not a code-writing service. Please [see here](http://stackoverflow.com/help/how-to-ask) to learn how to write effective questions. — Morgan Thrapp, Dec 08 '15 at 18:46

score 0 · Answer 1 · edited Dec 08 '15 at 18:51

0

new_dict={ k:v for k, v in mydict.iteritems() if v != 0 }

edited Dec 08 '15 at 18:51

Ahsanul Haque

answered Dec 08 '15 at 18:48

Suresh Mali

Ahsanul Haque · Answer 2 · 2015-12-08T19:04:03.993

0

This should help:

print dict(filter(lambda x:x[1] !=0,ab.iteritems()))

Output:

{'QUARTER': 5, 'HALF DOLLAR': 3, 'DIME': 3}

edited Dec 08 '15 at 19:04

answered Dec 08 '15 at 18:50

Ahsanul Haque

2

Don't compare ints with `is`. It doesn't work the way you think it does. – user2357112 Dec 08 '15 at 19:03
Oh yes! You are right. Fixed. – Ahsanul Haque Dec 08 '15 at 19:05

2 Answers2