Text after % is not printing

Question

I was just completing my assignment when I noticed that the text after the % symbol in double quotes is not printing. Here is a very easy example to show this:

 //program
 #include<stdio.h>
 int main()
 {
      printf("remainder of 5%2 is : %d",5%2);//here %2 is not printing
      return 0;
 }

output:

remainder of 5 is : 1

Only the %2 is not printed by printf() rest everything is fine.

Enable more compiler warnings (e.g.`-Wall`). – Biffen Dec 10 '15 at 11:14 — Biffen, Dec 10 '15 at 11:14

score 3 · Accepted Answer · answered Dec 10 '15 at 11:12

3

Use %% to print %:

printf("remainder of 5%%2 is : %d",5%2);

answered Dec 10 '15 at 11:12

P.P

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score 0 · Answer 2 · answered Dec 10 '15 at 11:23

0

You can also use ASCII code:

printf("remainder of 5%c2 is : %d",37,5%2");

answered Dec 10 '15 at 11:23

NutCracker

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Text after % is not printing

2 Answers2