BASH: replace string like in javascript

Question

I have a variable in a Bash script, and I want to replace all occurrences of / in it with _ and all occurrences of + with -; and I want to remove all occurrences of =. So, if this were JavaScript, something like this:

str = str.replace(/\//g, "_").replace(/\+/g, "-").replace(/=/g, "");

How can I do this in Bash.

this is a dupe: http://stackoverflow.com/questions/13210880/replace-one-substring-for-another-string-in-shell-script — Hitmands, Dec 10 '15 at 18:15
@Hitmands Not strictly a dupe, as this question is about character translation (`tr` territory) whereas the proposed dupe is about longer strings (`sed` territory, though certainly the `y%/+/_-/` command of `sed` could come in handy here as well). — tripleee, Dec 11 '15 at 14:11

score 1 · Accepted Answer · answered Dec 10 '15 at 18:15

1

You can do this in BASH:

s='my/String+One=Two'
s="${s//\//_}"
s="${s//+/-}"
s="${s//=/}"
echo "$s"
my_String-OneTwo

answered Dec 10 '15 at 18:15

anubhava

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score 1 · Answer 2 · answered Dec 10 '15 at 18:26

1

echo "$string" | tr '/+''_-' | tr -d '='

answered Dec 10 '15 at 18:26

tripleee

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BASH: replace string like in javascript

2 Answers2