C++ How to replace number for letter

Question

well I would like to know how to change number by letter, I would like to replace the number 1 with :x: Here's my code:

string stng;

printf("Enter with number:");
cin >> stng;

replace(stng.begin(), stng.end(), '1', 'x');

cout << stng << endl;

as you can see I'm using this to replace: replace(stng.begin(), stng.end(), '1', 'x'); but as soon as I can only change 1 for x, I want to replace for :x:

http://stackoverflow.com/questions/4643512/… http://stackoverflow.com/questions/3418231/… I seems for C++ it is not so trivial task :(. — Dzenly, Dec 11 '15 at 04:16
Possible duplicate of [How to replace all occurrences of a character in string?](http://stackoverflow.com/questions/2896600/how-to-replace-all-occurrences-of-a-character-in-string) — prazuber, Dec 12 '15 at 14:37

score 0 · Answer 1 · answered Dec 11 '15 at 03:45

0

Maybe you can try something like this

string stng;

printf("Enter with number:");
cin >> stng;

replace(stng.begin(), stng.end(), '1', ":x:");

cout << stng << endl;

answered Dec 11 '15 at 03:45

bl4ckb0ne

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but its no possible give me a erro if i use 'x' no error ! :c – Ph4nton Dec 11 '15 at 04:45

Anon Mail · Answer 2 · 2015-12-11T05:01:33.533

0

Here's what I use. It will take a std::string and replace all occurrences of the from input string to the to input string.

std::string replaceAll(const std::string & s, const std::string & from, const std::string & to)
{
    string res(s);
    string::size_type n1 = from.size();
    string::size_type n2 = to.size();
    string::size_type i = 0;
    string::size_type j = 0;
    while ((i = res.find(from, j)) != string::npos)
    {
        res.replace(i, n1, to);
        j = i + n2;
    }
    return res;
}

edited Dec 11 '15 at 05:01

answered Dec 11 '15 at 04:52

Anon Mail

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I think there's a bug if the `from` string is empty. – Anon Mail Dec 11 '15 at 05:17
no, that's right, you are calling the from inside the while :D – Ph4nton Dec 11 '15 at 06:30

Ankit Acharya · Answer 3 · 2015-12-12T14:06:59.057

0

You can do that better with the replace member function of std::string.

auto pos = stng.find("1"); // search for 1 in the string
if (pos!=stng.npos)  // check if 1 is found
{
   stng.replace(pos, 1, ":x:");   // replace ":x:" starting from 'pos' to 'pos+1'
}

And your job is done !!!

edited Dec 12 '15 at 14:06

answered Dec 11 '15 at 06:44

Ankit Acharya

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1

Hum that's nice, is working very well! I had never seen "auto" in C ++ will study more about it! thx :D – Ph4nton Dec 11 '15 at 20:25

score 0 · Answer 4 · edited May 23 '17 at 12:16

You can split the string by delim '1' into tokens using this split function.

Then merge the string by ":x:" using the following function

std::string merge(const std::vector<std::string>& v, const std::string& glue)
{    
    std::string result;
    if(v.empty()) { return result; }
    result += v[0];
    for(size_t i = 1; i != v.size() ; i++)
    {
        result += glue;
        result += v[i];
    }
    return result;
}

std::string replace(const std::string& src, char delim, const std::string& glue)
{
    return merge(split(src, delim), glue); 
}

Live is here

C++ How to replace number for letter

4 Answers4