How to stop a loop on itself function in javascript?

Question

I've an function and a conditional in that function and I will create loop by 4 times and break without without thinking any conditional.

Here is my idea

    function test (){

       var i = 0;

       $.ajax({
           setup:,
           success:function(data){
            if(data.resp ==true){
               if(i<= 4){
                test();
                 break;
                  return false;
               }
               }else{
               success;
               }
            }
       })
i++;
    }

I know this function will not work but I don't know how to do

And so, what is expected behaviour? Calling 4 ajax requests using recursive method or what??? — A. Wolff, Dec 11 '15 at 09:59
If I understand correctly, you want to stop after 4 calls of test method. For this to happen you have to make variable 'i' global. — Valentin S., Dec 11 '15 at 10:00
Yes I will call only 4 times when data.res === true and I also break or stop this loop although data.res === true (still equal true) — DMS-KH, Dec 11 '15 at 10:01
@ValentinS. don't set it global, set it as recursive method parameter instead — A. Wolff, Dec 11 '15 at 10:03
I think you can pass a parameter for test function. function test(val). When you call test(), the `val` increase 1, so test(val+1) — dieuvn3b, Dec 11 '15 at 10:07

score 1 · Accepted Answer · answered Dec 11 '15 at 10:06

1

To call it recursively keeping i local, you could use:

(function test(i) {
  $.ajax({
    url: 'uriThere.com',
    success: function(data) {
      if (i < 4 && data.resp == true) {
        test(++i);
      }
    }
  });
})(0);

answered Dec 11 '15 at 10:06

A. Wolff

74,033
9
94
155

score 1 · Answer 2 · 2015-12-11T10:15:28.680

1

Either make the var i = 0 variable outside of the function or try

function test (varI){

   var i = varI;

   $.ajax({
       setup:,
       success:function(data){
        if(data.resp ==true){
           if(i<= 4){
               test(++i);
               return false;
           }else{
               success;
           }
        }
    })
    i++;
}

edited Dec 11 '15 at 10:15

answered Dec 11 '15 at 10:07

This is wrong: `test(i++)` must be `test(++i)` and remove `i++;` – A. Wolff Dec 11 '15 at 10:08
@A.Wolff what is difference betwen ++i and i++? – DMS-KH Dec 11 '15 at 10:09
@HengSopheak http://stackoverflow.com/questions/24853/what-is-the-difference-between-i-and-i In this answer, this works because extra `i++` and end of test() method, but what happen is that using `test(i++)` you pass value of `i` before it is incremented, while using `test(++i)` you pas incremanted value. – A. Wolff Dec 11 '15 at 10:10
@A.Wolff Thanks. Missed that. So used to incrementing in for loops :P – Dec 11 '15 at 10:17

How to stop a loop on itself function in javascript?

2 Answers2