Echo inside an echo - PHP

Question

I have this PHP-code:

        <!-- PHP bliver brugt til dynamisk at hente madtabeldata fra 'datatab'-->
        <?php
            // Forbinder til database
            $db = include("connect2db.php");
            // Viser danske bogstaver
            $db->set_charset("utf8");

            // SQL query henter al data fra 'datatab' 
            $query="select * FROM datatab";

            $result = $db->query($query); // Placerer resultaterne af query i en variabel
            $num_results = $result->num_rows; 

            // Viser hver rækkes data i en tabel
            for ($i=0; $i <$num_results; $i++)
            {
                $row = $result->fetch_assoc();
                echo "<tr>";
                echo '<td>'.$row['dato'].'</td>
                      <td>'.$row['vaegt'].'</td>
                      <td>'.$row['motion'].'</td>
                    </tr>';
            }
        ?>
    </table>            
</div>

I want to include this echo inside my PHP-code:

<?php
    if (isset ($_SESSION['username'])) {
        echo '*PHP-code*';
    } else {
        echo '<p>"Please log in to see the table"</p>';
    }
?>

How can I do this successfully? When I enter it, it says that there is an error in the server.

you cannot do something like this.... if a echo is included in a single or double e quote it will be treated like any other ordinary string, where echo is nothing else but a word. when you open this in the browser you will see echo written on the page with brackets and else statement. — Meenesh Jain, Dec 12 '15 at 14:44
It's not clear what you're trying to do or what is failing. Though the code formatting in your question is clearly resulting in syntax errors. — David, Dec 12 '15 at 14:47
Why can't you just execute the PHP code instead of putting it in a string? Please show us what ``*PHP Code*`` would be. — Sander Toonen, Dec 12 '15 at 14:48
Well, there's [`eval()`](http://php.net/manual/en/function.eval.php), but if you find yourself in a situation where you think you need to use it, then it might time to step back and think about your approach. http://stackoverflow.com/questions/951373/when-is-eval-evil-in-php — Darragh Enright, Dec 12 '15 at 15:30

score 1 · Answer 1 · answered Dec 12 '15 at 15:31

You cannot echo "inside" an echo. You have to just copy your code there without the echos.

 <?php
    if (isset ($_SESSION['username'])) {
      // Forbinder til database
      $db = include("connect2db.php");
      // Viser danske bogstaver
      $db->set_charset("utf8");

      // SQL query henter al data fra 'datatab' 
      $query="select * FROM datatab";

      $result = $db->query($query); // Placerer resultaterne af query i en variabel
      $num_results = $result->num_rows; 
      echo "<div><table>";
      // Viser hver rækkes data i en tabel
      for ($i=0; $i <$num_results; $i++)
      {
        $row = $result->fetch_assoc();
        echo "<tr>";
        echo '<td>'.$row['dato'].'</td>
        <td>'.$row['vaegt'].'</td>
        <td>'.$row['motion'].'</td>
        </tr>';
      }
      echo "</table></div>";
   }
   else {
     echo '<p>"Please log in to see the table"</p>';
   }
?>

Alternatively you can put all your table in a string var and then echo that var:

<?php
    // Forbinder til database
    $db = include("connect2db.php");
    // Viser danske bogstaver
    $db->set_charset("utf8");

    // SQL query henter al data fra 'datatab' 
    $query="select * FROM datatab";

    $result = $db->query($query); // Placerer resultaterne af query i en variabel
    $num_results = $result->num_rows; 
    $table = "<table>";
    // Viser hver rækkes data i en tabel
    for ($i=0; $i <$num_results; $i++)
    {
        $row = $result->fetch_assoc();
        $table .= "<tr>";
        $table .= '<td>'.$row['dato'].'</td>
              <td>'.$row['vaegt'].'</td>
              <td>'.$row['motion'].'</td>
            </tr>';
    }
    $table .= "</table>";
?>

and later...

echo $table

but do not connect to db and elaborate the table if user is not connected of course.

Now I see the problem I was having. Can't echo inside an echo. Thanks — brewpixels, Mar 30 '16 at 08:48

Echo inside an echo - PHP

1 Answers1