Why I get a memory address using lambda function in Python?

Question

I´m new in Python and I guess this is a very simple question because I can´t find an answer. I have this code:

Celsius = [39.2, 36.5, 37.3, 37.8]
Fah = map(lambda x: (float(9)/5)*x + 32, Celsius)
print(Fah)

I expect to get:

>>> [102.56, 97.700000000000003, 99.140000000000001, 100.03999999999999]

But I get:

>>> <map object at 0x000000000909CA20>

In python 3.X `map` returns a `map object` which is an iterator like object. If you want to get a `list()`, you need to call the list function on your result. — Mazdak, Dec 14 '15 at 15:13

score 2 · Accepted Answer · answered Dec 14 '15 at 15:15

2

map() returns a generator, to view it convert it to list:

Fah = map(lambda x: (float(9)/5)*x + 32, Celsius)
print(list(Fah))

answered Dec 14 '15 at 15:15

mirosval

score 0 · Answer 2 · answered Dec 14 '15 at 15:15

0

Change:

print(Fah)

to:

print(list(Fah))

answered Dec 14 '15 at 15:15

RD3

2 Answers2