sed extract every occurrence of string between specific delimiters

Question

How to extract characters between delimiters ":" for all occurrences in a line (defined as strings separated by white-space) for all lines? I have tried sed 's/.:(.):.*//g' but that doesn't take into account multiple occurrences.

given:

1/1:2.000:0.000,0.000,1.000 0/1:1.001:0.000,0.999,0.001
1/1:2.000:0.000,0.000,1.000 0/1:1.002:0.000,0.998,0.002

to be obtained:

2.000 1.001
2.000 1.002

Does this answer your question? [How to extract characters between the delimiters using sed?](https://stackoverflow.com/questions/7684729/how-to-extract-characters-between-the-delimiters-using-sed) — tripleee, Feb 09 '21 at 08:21

score 1 · Accepted Answer · answered Dec 14 '15 at 21:29

1

This might work for you (GNU sed):

sed -r 's/[^:]*:([^:]*):\S*(\s)*/\1\2/g' file

answered Dec 14 '15 at 21:29

potong

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sed extract every occurrence of string between specific delimiters

1 Answers1