php json decode object with array of multiple objects

Question

I am unable to get values of array of this json... how can i have all these values seperately!!

{
    "id": "jai",
    "pwd": "123",
    "user": [
        {
            "fname": "jai",
            "lname": "gupta"
        },
        {
            "fname": "sameer",
            "lname": "seth"
        }
    ],
    "college": "vit"
}

I am able to get all values except array. i want to store all users information to db. that's i want to do with this json — Mohit Gupta, Dec 15 '15 at 08:27

score 1 · Accepted Answer · answered Dec 15 '15 at 07:43

1

$myArray = json_decode($json, true);

var_dump($myArray['id']);
var_dump($myArray['user'][0]['fname']);

answered Dec 15 '15 at 07:43

Mihai Matei

24,166
5
32
50

bIgBoY · Answer 2 · 2015-12-15T07:58:20.157

0

You can access each "value" by accessing regular php array key value pairs.

$jsonn = '{"id":"jai","pwd":"123","user":[{"fname":"jai","lname":"gupta"},{"fname":"sameer","lname":"seth"}],"college":"vit"}';
$new = json_decode($jsonn, true);

$id = $new['id'];
$user = $new['user'];
..... and so on.

Hope this helps.

Cheers!

edited Dec 15 '15 at 07:58

answered Dec 15 '15 at 07:43

bIgBoY

417
2
12

use `assoc` parameter when docode the json if you want to access with key index. – check Dec 15 '15 at 07:57
@check missed that, thanks! – bIgBoY Dec 15 '15 at 07:58

score 0 · Answer 3 · answered Dec 15 '15 at 07:45

0

You can decode these values from json to object.

$result = json_decode('{"id":"jai","pwd":"123","user":[{"fname":"jai","lname":"gupta"},{"fname":"sameer","lname":"seth"}],"college":"vit"}');

and acccess like below:

$result->id; 
$result->pwd;

answered Dec 15 '15 at 07:45

vaths

73
6

php json decode object with array of multiple objects

3 Answers3