Replace and get word occurrence count

Question

I have a string, I want to replace the specific word and also want to count the number of occurrence. e.g

"Of course, there are many other open source or commercial tools available.
Twitter typeahead is probably the most important open source alternative."
.replace(/source/g,'<b>source</b>');

This will replace all source with <b>source</b> but I want the count of occurance of source also i.e 2.

It is not possible to return 2 values with `replace`. Still you can use a counter and increment it inside a callback function. Are you looking for this: https://jsfiddle.net/028etoLg/? — Wiktor Stribiżew, Dec 16 '15 at 08:35

Rahul Tripathi · Answer 1 · 2015-12-16T06:41:43.180

1

Before the replace call you can simply do:

var count = ("Of course, there are many other open source or commercial tools available.    Twitter typeahead is probably the most important open source alternative.".match(/source/g) || []).length;
var replaceString = "Of course, there are many other open source or commercial tools available.Twitter typeahead is probably the most important open source alternative."
.replace(/source/g,'<b>source</b>');
alert(count);
alert(replaceString);

edited Dec 16 '15 at 06:41

answered Dec 16 '15 at 06:35

Rahul Tripathi

168,305
31
280
331

isn't it two step process ? – Manish Kumar Dec 16 '15 at 06:36
i want both new replaced string and count both – Manish Kumar Dec 16 '15 at 06:40
@Manish:- Updated the code. You have done your 1st step already. To count the occurence of the matched string you can do like above. – Rahul Tripathi Dec 16 '15 at 06:42
is it possible to it one go ? – Manish Kumar Dec 16 '15 at 06:45
@Manish:- I dont think it is! – Rahul Tripathi Dec 16 '15 at 06:46

score 1 · Answer 2 · answered Dec 16 '15 at 06:36

1

function replaceAndCount(str, tofind, rep){

   var _x = str.split(tofind);
   return{
     "count":_x.length-1,
     "str":_x.join(rep)
   };

}

Something like this function.

Now the count will be

var str = "Of course, there are many other open source or commercial tools available.
Twitter typeahead is probably the most important open source alternative.";
var count = replaceAndCount(str, "source", "<b>source</b>").count;

and new string will be

var newString = replaceAndCount(str, "source", "<b>source</b>").str.

answered Dec 16 '15 at 06:36

void

36,090
8
62
107

is it possible to it one go ? – Manish Kumar Dec 16 '15 at 06:45
What do you mean in one go? – void Dec 16 '15 at 06:48

gurvinder372 · Answer 3 · 2015-12-16T08:02:09.670

0

why not split and join?

function replaceAndCount( str, toBeReplaced, toBeReplacedBy )
{
  var arr = str.split( "toBeReplaced" );

  return [ arr.join( toBeReplacedBy  ), arr.length ];
}  

replaceAndCount( "Of course, there are many other open source or commercial tools available. Twitter typeahead is probably the most important open source alternative." , "source", "<b>source</b>");

edited Dec 16 '15 at 08:02

answered Dec 16 '15 at 06:34

gurvinder372

66,980
10
72
94

score 0 · Answer 4 · answered Dec 16 '15 at 06:35

0

you can first count the occurencies like this

var occurencies = (string.match(/source/g) || []).length;

and then replace them

answered Dec 16 '15 at 06:35

Giannis Tzagarakis

522
6
27

score 0 · Answer 5 · answered Dec 16 '15 at 08:41

It is not possible to return 2 values (both the replaced string and the replacement count) with replace.

However, you can use a counter and increment it inside a callback function.

var count = 0; // Declare the counter
var res = "Of course, there are many other open source or commercial tools available.Twitter typeahead is probably the most important open source alternative.".replace(/source/g,function(m) { count++; return '<b>source</b>';}); 

// demo check
document.getElementById("r").innerHTML = "Result: " + res;
document.getElementById("r").innerHTML += "<br/>Count: " + count;

<div id="r"/>

Replace and get word occurrence count

5 Answers5