DEV C++ incompatible types in assignment of `const char[10]' to `char[21]'

Question

#include<iostream>
#include<conio.h>
using namespace std;
struct Infor{
       char name[21];

       }infot[4];
int main()
{
    infot[0].name="PROGRAM 1";
    cout<<infot[0].name;
    getch();
    return 0;
}

The code is used to initialize a string into a structure containing a char variable.

score 3 · Answer 1 · answered Dec 16 '15 at 14:35

3

You should use strcpy() to copy c-style strings.

#include<iostream>
#include<cstring>
using namespace std;
struct Infor{
       char name[21];
       int acn;
       int pin;
       int balance;
       }infot[4];
int main()
{
    strcpy(infot[0].name, "PROGRAM 1");
    cout<<infot[0].name;
    return 0;
}

Alternatively, std::string may be useful.

#include<iostream>
#include<string>
using namespace std;
struct Infor{
       string name;
       int acn;
       int pin;
       int balance;
       }infot[4];
int main()
{
    infot[0].name = "PROGRAM 1";
    cout<<infot[0].name;
    return 0;
}

answered Dec 16 '15 at 14:35

MikeCAT

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1

It's not really good practice to use `using namespace std;` – owacoder Dec 16 '15 at 14:37
Thanks man. Works like a charm. And I'm new to programming so why should i not use using namspace std;? – user5687110 Dec 16 '15 at 14:40
See [this question](http://stackoverflow.com/questions/1452721/why-is-using-namespace-std-considered-bad-practice). – owacoder Dec 16 '15 at 14:42

DEV C++ incompatible types in assignment of `const char[10]' to `char[21]'

1 Answers1