Reading particular String from a line

Question

I am using this to get each line from a text file using Java Class.

String line = null;
try{    
       BufferedReader Br=new BufferedReader(new FileReader("/data/local/fileconfig.txt"));   

       while ((line = Br.readLine()) != null)
        {
           Log.d("hi", "LINE : " + line);              
        }
     } catch (Throwable throwable) { }

The fileconfig.txt has 2 lines like this -

############################################
packagename:com.hello

So my Log is like -

LINE :  ############################################
LINE :  packagename:com.hello

My question is now I am able to get this line info packagename:com.hello. I just want to extract com.hello out of this line. What is the logic I can use in my while loop?

Try a regex. group 1 in "packagename:\\s*([^\\s]+)" would contain your result. — Jan, Dec 16 '15 at 14:47

score 3 · Answer 1 · edited May 23 '17 at 11:44

3

You could use the startsWith() method.

Or, somewhat more powerful, but also more difficult, use Regular Expressions with Match Groups.

See here: Using Java to find substring of a bigger string using Regular Expression

edited May 23 '17 at 11:44

Community

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1

answered Dec 16 '15 at 14:47

Rob Audenaerde

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score 2 · Accepted Answer · answered Dec 16 '15 at 14:47

2

If the format of line is always the same then this should do:

Log.d("hi", "LINE : " + line.substring(line.lastIndexOf(":")+1));

answered Dec 16 '15 at 14:47

Darshan Mehta

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This is giving me output as - LINE : ############################################ LINE : com.hello – FAZ Dec 16 '15 at 15:37
@FAZ Don't read the 1st line, break it or use a `startsWith("package");` – Uma Kanth Dec 16 '15 at 15:48

score 1 · Answer 3 · answered Dec 16 '15 at 14:48

1

You can use either RegEx or a simple split() from String

:?(.*)

or split

String myString = "dsd:Example";
myString.split(":");

answered Dec 16 '15 at 14:48

Marcinek

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Reading particular String from a line

3 Answers3