Sort out a List in Java 7

Question

I have a data structure of type List<Map<String, String>> and I am looking to sort out all the Map values inside the List as per the value. For example - the list when iterated gives a Map which consists of two key value pairs.

Map1--> Key1:  abc and key2: Sometext2
Map2 --> Key1: cbd and key2: Sometext2
Map3 --> Key1: bcd and key2: Sometext2
.
.
.
.

and so on. I am looking to sort alphabetically the data structure by the values mapped to key1 so it should look like:

Map1--> Key1:  abc and key2:Sometext2.
Map3 --> Key1: bcd and key2: Sometext2
Map2 --> Key1: cbd and key2: Sometext2
.
.
.
.

I am using Java 7. Any help is highly appreciated.

Thanks

Yeah I understand I have to implement a comparator but not able to sort out the logic. — user972418, Dec 17 '15 at 18:46
If all the maps have two key/value pairs, with the same keys each time, perhaps you should create a class for that instead? — Jon Skeet, Dec 17 '15 at 18:46
http://stackoverflow.com/questions/5155952/sorting-a-list-of-mapstring-string?rq=1 — , Dec 17 '15 at 19:14

score 0 · Answer 1 · answered Dec 17 '15 at 18:52

Based on your example, your Map is simply a couple (String, String).

So we can do:

public class MyCouple {
    private String first;
    private String second;
    // + constructors, getters, setters
}

List<MyCouple> couples = // ...
Collections.sort(couples, new Comparator<MyCouple>(){
    @Override
    public int compare(MyCouple c1, MyCouple c2) {
        return c1.getSecond().compareTo(c2.getSecond()); // sort by second
    }
});

score 0 · Answer 2 · answered Dec 17 '15 at 18:55

You could use a wrapper class for the map and then get the iterator for your list. Something like this:

class MapWrapper implements Comparable<Map> {
    private Map<String, String> map;

    public MapWrapper (Map<String, String> map) {
        this.map = map;
    }

    public int compareTo() {
        do stuff
    }
}

score 0 · Answer 3 · answered Dec 17 '15 at 18:55

I had a similar requirement and I developed a comparable map. Class declaration is:

public class ComparableMap<K,V> extends TreeMap<K,V> implements Comparable<ComparableMap<K,V>> {
    @Override
    public int compareTo(ComparableMap<K,V> o) {...}
}

Since TreeMap iterator returns keys sorted, to compare 2 maps, you iterate through the keys, comparing each key until either keys are not equal, or for equal keys, values are not equal, returning the appropriate result depending on which is less. When reach end of one keyset, if other has keys, then they are also not equal, and you would return appropriate compare result.

Finally, you can then use Collections.sort() to sort the list of maps, since the compareTo method will be used to determine the sort order.

Hope this give you some ideas.

If you want individual keys across all maps sorted, you'll probably have generate a merged map.

You can implement compareTo() as necessary to order your maps appropriately. — DBug, Dec 17 '15 at 18:57

score 0 · Answer 4 · answered Dec 17 '15 at 21:25

Try this

static <T> Map<String, T> makeMap(String k1, T v1, String k2, T v2) {
    Map<String, T> map = new LinkedHashMap<>();
    map.put(k1, v1);
    map.put(k2, v2);
    return map;
}

public static void main(String[] args) {
    List<Map<String, Integer>> list = Arrays.asList(
        makeMap("abc", 1, "Sometext2", 1),
        makeMap("cde", 2, "Sometext2", 2),
        makeMap("bcd", 3, "Sometext2", 3)
    );
    System.out.println("before: " + list);
    Collections.sort(list, new Comparator<Map<String, Integer>>() {

        @Override
        public int compare(Map<String, Integer> o1, Map<String, Integer> o2) {
            return o1.keySet().iterator().next()
                .compareTo(o2.keySet().iterator().next()); 
        }

    });
    System.out.println("after:  " + list);
}

Results:

before: [{abc=1, Sometext2=1}, {cde=2, Sometext2=2}, {bcd=3, Sometext2=3}]
after:  [{abc=1, Sometext2=1}, {bcd=3, Sometext2=3}, {cde=2, Sometext2=2}]

Sort out a List in Java 7

4 Answers4