We'll get to the point...
I have a simple form (2 of them) that relies off the previous filled out.
The intention of these forms are to sign, post to db, validate email. After the user validates their email their permission will change to be able to see the next form.
These forms work great, and everything is functional in exception to this last bit.
I am having difficulty with the form applying the values to the db table when there is existing user.
What I would like to do is only have it update the keys
for that user where users session-ed API
key =$API
AND form_ica_initials
is NULL in the roster
table. If it does then will INSERT INTO
Here is what I have cleaned up. (originally wrote for the first phase of the forms to be filled out, trying to tweak to work for last half of forms)
if (empty($_POST['initials'])) { $error[] = 'You must enter your initials in every box below.'; }
else { $initials = $_POST['initials']; }
$API = $_SESSION['API'];
if (empty($error)) {
$query_verify_form = "SELECT * FROM roster WHERE API ='$API'";
$result_verify_form = mysqli_query($dbc, $query_verify_form);
if (!$result_verify_form) {
echo ' Database Error Occured ';
}
if (mysqli_num_rows($result_verify_form) == 0) {
$form_icaauth = md5(uniqid(rand(), true));
error_reporting(E_ALL);
$query_insert_user = "UPDATE `roster`
(
`fullname`, `form_ica_initials`, `form_icaauth`,`form_ica_ip`
)
VALUES (
'$fullname', '$initials', '$form_icaauth','$DOCSIGNEDBYIP'
)
";
$result_insert_user = mysqli_query($dbc, $query_insert_user);
if (!$result_insert_user) {
echo 'Query Failed ';
}
if (mysqli_affected_rows($dbc) == 1) {
...
echo '<br><center><div class="success">...</div>';
}
else {
echo '<center><div class="error">...</div></center>';
}
}
else {
echo '<center><div class="warning" >...</div></center>';
}
}
else {
echo '<center><div class="info"> <ol>';
foreach ($error as $key => $values) {
echo ' <li>' . $values . '</li>';
}
echo '</ol></div></center>';
}
mysqli_close($dbc); //Close the DB Connection
}
If I change the if (mysqli_num_rows($result_verify_form) == 0) {
to ==1
It will post the values to the table by creating a new record, and not update the existing users fields as specified. However, by doing that it will circumvent the errors that I have structured.
I know my way around PHP a bit... but having difficultly with this one