Issue with reading file content using linux

Question

I want to read contents of a file using a linux shell script. The contents of file_list.txt is:

abc
def
ghi

And the script to read this is read_file_content.sh:

#!/bin/bash

for file in $(cat file_list.txt)
do
 "processing "$file
done

When I run the command as ./read_file_content.sh, I get the following error:

./read_file_content.sh: line 6: processing abc: command not found
./read_file_content.sh: line 6: processing def: command not found
./read_file_content.sh: line 6: processing ghi: command not found

Why does this print 'command not found'?

I tried using while loop but its not reading the last line from the file — Muhammad, Dec 18 '15 at 10:33
I guess yours isn't a valid text file, then. Working around that is covered in http://stackoverflow.com/questions/12916352/shell-script-read-missing-last-line — tripleee, Dec 18 '15 at 10:41
using while read line || [ -n "$line" ]; do echo $line; done < y — Muhammad, Dec 18 '15 at 11:15

score 4 · Accepted Answer · edited Apr 13 '17 at 12:36

You wrote "processing "$file without any command in front of it. Bash will take this literally and try to execute it as a command. To print the text on the screen, you can use echo or printf.

Echo example

echo "processing" "$file"

Printf example

printf "%s\n" "$file"

(This is the recommend way if you're going to process weird filenames that contain - and space characters. See Why is printf better than echo?)

Notice the way I did the quotes, this prevents problems with filenames that contain special characters like stars and spaces.

Issue with reading file content using linux

1 Answers1