I found the answer here but it doesn't work for me Accessing the index in Python 'for' loops
I'm trying to loop from the second index
ints = [1, 3, 4, 5, 'hi']
for indx, val in enumerate(ints, start=1):
print indx, val
for i in range(len(ints)):
print i, ints[1]
My output is this
1 1
2 3
3 4
4 5
5 hi
0 3
1 3
2 3
3 3
4 3
I need to get the first integer printed out at index 1 and loop through to the end.
A simple way is to use python's slice notation - see the section in the basic tutorial. https://docs.python.org/2/tutorial/introduction.html
for item in ints[1:]:
This will iterate your list skipping the 0th element. Since you don't actually need the index, this implementation is clearer than ones that maintain the index needlessly
Try
for idx, val in enumerate(ints[1:], start=1)
print idx, val
Or
for i in range(1, len(ints)):
print i, ints[i]
I'm not sure I fully understand what you're trying to achieve. To my understanding, if you just want to loop through the list starting at the second element you can do this:
ints = [1, 3, 4, 5, 'hi']
for i in range(1,len(ints)):
print i, ints[i]
output:
1 3
2 4
3 5
4 hi
Alternatively, if you want to loop through all elements, but print the indices starting from 1 instead of 0:
ints = [1, 3, 4, 5, 'hi']
for i in range(len(ints)):
print i+1, ints[i]
output:
1 1
2 3
3 4
4 5
5 hi
Or using enumerate() going through all elements, but print the indices starting at 1 instead of 0:
ints = [1, 3, 4, 5, 'hi']
for i, el in enumerate(ints):
print (i+1), el
output:
1 1
2 3
3 4
4 5
5 hi
You could use itertools.islice:
import itertools
for idx, el in enumerate(itertools.islice(ints, 1, None), start=1):
print(idx, el)
Or if you just want to skip the first element:
for idx, el in enumerate(ints):
if idx == 0:
continue
print(idx, el)
A solution for iterables too (not only lists):
def enumerate_from(start_index, iterable):
for i, x in enumerate(iterable):
if i >= start_index:
yield i, x
