Not receiving the parameters containing '?' properly. The part after '?' is getting trimmed. How do I avoid it?

Question

I am writing a Django application. In my 'urls.py' I have written a URL pattern like this:

url(r'^rest/post/(.*)/$', rest_post),

Now when I am passing some URL like:

http://www.google.com/a?b

In my rest_post view I am getting only: http://www.google.com/a

I want to get the full URL. How do I do it?

Most people would consider your `a` and your `b` very different things (path and search string, respectively). URL matching is normally done on URLs up to but not including the search string. — Amadan, Dec 21 '15 at 04:03
@Amadan Actually I am building a URL shortener. So I need to pass the URL to my views in order to process it. Is there any way I can do that? — anirban.at.web, Dec 21 '15 at 04:06
See the linked question on how to get the original request path; or you can see [other methods of `request`](https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.get_full_path) for fetching any other request datum. — Amadan, Dec 21 '15 at 04:08

score 1 · Answer 1 · answered Dec 21 '15 at 04:10

1

simply

request.get_full_path()

in your views.

answered Dec 21 '15 at 04:10

doniyor

Cool it works! Note: But then I was getting "/rest/post/http://www.google.com/a/?b". So I manually trimmed off the first part like this: request.get_full_path()[11:] – anirban.at.web Dec 21 '15 at 04:22
No. I want to get "http://www.google.com/a?b". That is, the whole parameter that was passed. – anirban.at.web Dec 21 '15 at 04:28
@anirban.at.web ok got you – doniyor Dec 21 '15 at 04:32

1 Answers1