Program in Python for alphabets in pattern

Question

I have written this program:

for i  in range(1,6):
    for j in range(65,65+i):
        a =  chr(j)
        print (a)
    print

I want to print a pattern as follows:

A
A B
A B C
A B C D
A B C D E

but i am not getting the desired output

i am getting

A

A
B

A
B
C

A
B
C
D

A
B
C
D
E

Did you try with `print a,`? The comma makes the output on the same line. — Delgan, Dec 21 '15 at 19:41

score 5 · Answer 1 · edited Dec 21 '15 at 19:59

5

In python 2, simply put a comma after the print statement:

for i in range(1, 6):
    for j in range(65, 65+i):
        a = chr(j)
        print a,
    print

For python 3, or in python 2 using from __future__ import print_function you would do something like this:

for i in range(1, 6):
    for j in range(65, 65+i):
        a = chr(j)
        print(a, end=" ")
    print()

Note that I put a space (" ") as the end character. You could set it to "" and the output will be without spaces, like so:

A
AB
ABC
ABCD
ABCDE

edited Dec 21 '15 at 19:59

Sebastian Kreft

7,819
3
24
41

answered Dec 21 '15 at 19:48

jgritty

11,660
3
38
60

with `from __future__ import print_function` the Python 3 version, will also work in Python 2.6 and newer. – AlexV Dec 21 '15 at 19:50

Padraic Cunningham · Answer 2 · 2015-12-21T20:26:22.947

3

You can also use str.join using string.ascii_uppercase:

from string import ascii_uppercase
for i in range(1, 6):
    print(" ".join(ascii_uppercase[:i]))

Or using your range logic:

for i in range(1, 6):
    print(" ".join(chr(j) for j in range(65, 65 + i)))

edited Dec 21 '15 at 20:26

answered Dec 21 '15 at 20:18

Padraic Cunningham

176,452
29
245
321

1

I was just typing this answer, mostly because constructing the string A-E and printing it in one go is much faster than calling print 6 times to print each letter individually and a newline. – Reti43 Dec 21 '15 at 20:23

score 1 · Answer 3 · edited May 23 '17 at 12:07

1

print a (or print (a)) will print a newline. If you want to suppress the newline you can write

print a,

For more infos see the question: Printing without newline (print 'a',) prints a space, how to remove?

edited May 23 '17 at 12:07

Community

1
1

answered Dec 21 '15 at 19:43

Jakube

3,353
3
23
40

There is also a nice SO answer which differentiates by the different Python versions [here](http://stackoverflow.com/a/493399/5682996) – AlexV Dec 21 '15 at 19:46

score 0 · Answer 4 · edited Jul 12 '17 at 11:35

0

Just put a comma after print(a) in python 3.

In python 2 you just put end=" " inside of print(a,end=" ")

#!usr/bin/env python
for i  in range(1,6):
    for j in range(65,65+i):
        a =  chr(j)
        print (a),
        print

edited Jul 12 '17 at 11:35

Eric Aya

69,473
35
181
253

answered Jul 12 '17 at 10:32

VIJAYAKUMAR R

1

score 0 · Answer 5 · edited Jul 29 '19 at 14:00

0

n=int(input())
for i in range(1,n+1):
    print(" ")
    for j in range(65,65+i):
        a=chr(j)
        print(a,end=" ")
    print

edited Jul 29 '19 at 14:00

Aymen

1,476
18
28

answered Jul 29 '19 at 13:46

Vijaya Praveena Eranki

1

score 0 · Answer 6 · answered Sep 12 '19 at 15:17

The problem with your code is that you are not using end=" " in print statement, it is required to use end=" " because python print() function by default print in new line, thats why at every iteration it is jumping into new line. Correction to your code is:

for i in range(1,6):
    print(" ")
    for j in range(65,65+i):
        print(chr(j),end=" ")
    print("")

score 0 · Answer 7 · answered Nov 08 '20 at 06:36

0

for i  in range(1,6):
for j in range(65,65+i):
    a =  chr(j)
    print (a, end = " ")
print()

Here, the modification is in the first print statement where I just have added the end parameter.

answered Nov 08 '20 at 06:36

Krishnendu Biswas

11
3

score -2 · Answer 8 · edited Feb 20 '19 at 16:41

for i  in range(1,6):
    for j in range(65,65+i):
        a =  chr(j)
        print (a)
        print("")

output:

Program in Python for alphabets in pattern

8 Answers8