Don't want to pollute an object's prototype. How to have prototype inheritance w/ namespace?

Question

I don't want to pollute the prototype of objects with all my library's methods. I want to hide them inside a __namespace property.

When you try to access an object property, if it is undefined, it will look up the prototype chain like so

a.c -> a.prototype.c -> a.prototype.prototype.c ..

I would like to achieve

a.__namespace.c -> a.prototype.__namespace.c, a.prototype.prototype.__namespace.c ...

Exemple :

function A(){};
A.prototype.__namespace = {};
A.prototype.c = 2; // normal 
A.prototype.__namespace.c = 2; // inside namespace

var a = new A();
a.__namespace = {};
console.log(a.c) // prints 2
console.log(a.__namespace.c); //undefined. Would like to print 2.

Is there a javascript functionality that allows this other than creating it like :

function NameSpace(){}
NameSpace.prototype.c = 3;

var a = new A();
a.__namespace = new NameSpace();
console.log(a.__namespace);

Check this fiddle.

you are overwriting value of namespace by initializing a.namespace={} — Sundar Singh, Dec 22 '15 at 07:25
If you want parents value you need not to do a.namespace= {} — Sundar Singh, Dec 22 '15 at 07:27
It overwrite the value of namespace.b by using a.namespace.b=3 — Sundar Singh, Dec 22 '15 at 07:28
I am asking if there is a way that if a.__namespace.c is undefined on the instance, that it will look up the prototype chain — Ludovic C, Dec 22 '15 at 07:29
Just like if you write a.c, if a.c is undefined, it will look for a.prototype.c, a.prototype.prototype.c ... Now, I want a.__namespace.c, a.prototype.__namespace.c, a.prototype.prototype.__namespace.c, a.prototype.prototype.__namespace.c — Ludovic C, Dec 22 '15 at 07:30
You're looking for `a.__namespace = Object.create(A.prototype.__namespace);` — Bergi, Dec 22 '15 at 07:37
If you remove line a.__namespace = {}; then it will print 2. — Sundar Singh, Dec 22 '15 at 07:37
@SundarSingh I think you did not understand the question.. I want to be able to redefine properties on the instance also. — Ludovic C, Dec 22 '15 at 07:40

JosephGarrone · Answer 1 · 2015-12-22T07:50:25.033

0

I just Fiddled around and came up with that. I'm not 100% sure if it's what you are intending.

Essentially I am storing the prototyped functions in a single property of the prototype.

SomeObject.prototype.someNamespace = Object.create(SomeOtherObject.prototype);

Of course, the SomeOtherObject will have to have a polluted prototype.

ATTEMPT 2

I tried again. Is this what you are intending?

edited Dec 22 '15 at 07:50

answered Dec 22 '15 at 07:31

JosephGarrone

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Thanks for your answer, but that's not it. Check the updated question. – Ludovic C Dec 22 '15 at 07:33

Don't want to pollute an object's prototype. How to have prototype inheritance w/ namespace?

1 Answers1