PHP REGEX: Get domain from URL

Question

What I want

I want to get from a URL the domain part so from http://example.com/ -> example.com

Examples:

+----------------------------------------------+-----------------------+
| input                                        | output                |
+----------------------------------------------+-----------------------+
| http://www.stackoverflow.com/questions/ask   | www.stackoverflow.com |
| http://validator.w3.org/check                | validator.w3.org      |
| http://www.google.com/?q=hello               | www.google.com        |
| http://google.de/?q=hello                    | google.de             |
+----------------------------------------------+-----------------------+

I found some related questions in stackoverflow but none of them was exactly what I was looking for.

Thanks for any help!

This code will help you get the complete domain name: https://gist.github.com/praisedpk/64bdb80d28144aa78d58469324432277 — Hamid Sarfraz, Sep 18 '16 at 20:27

score 82 · Accepted Answer · answered Aug 09 '10 at 17:04

82

There's no need to use a regex for this. PHP has an inbuilt function to do just this. Use parse_url():

$domain = parse_url($url, PHP_URL_HOST);

answered Aug 09 '10 at 17:04

cletus

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2

it good only if containing http(s) , not for "stackoverflow.com/questions" – ewwink Jan 27 '14 at 05:20
1

this will also give you subdomains. Be careful because `parse_url('http://example.com', PHP_URL_HOST) == parse_url('http://www.example.com', PHP_URL_HOST)` will return false – Jonathan Morales Vélez May 13 '15 at 22:30

score 4 · Answer 2 · edited May 17 '16 at 14:52

4

I use:

$domain = parse_url('http://' . str_replace(array('https://', 'http://'), '', $url), PHP_URL_HOST);

Because parse_url doesn't return host key when schema is missing in $url.

edited May 17 '16 at 14:52

aniski

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answered May 17 '16 at 13:51

Marcin Żurek

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score 2 · Answer 3 · edited May 23 '17 at 12:02

2

This is like the regex from theraccoonbear but with support for HTTPS domains.

if (preg_match('/https?:\/\/([^\/]+)\//i', $target_string, $matches)) {
  $domain = $matches[1];
}

edited May 23 '17 at 12:02

Community

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answered Dec 06 '13 at 08:29

fnkr

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score 2 · Answer 4 · answered Aug 09 '10 at 17:07

2

$tmp = parse_url($url);
$url = $tmp['host']

answered Aug 09 '10 at 17:07

turbod

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score 1 · Answer 5 · answered Aug 09 '10 at 17:04

1

Assumes that http:// prefixes everything.

$tmp = explode("/", $url);
$domain = $tmp[2];

answered Aug 09 '10 at 17:04

Josh K

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heh, most out-of-the-box solution :-) – gnud Aug 09 '10 at 18:01

score 1 · Answer 6 · answered Jul 27 '19 at 05:36

I think the following regexp might answers your question.

This diagram explains how it works, or rather why it works :-)

$regexp = '/.*\/\/([^\/:]+).*/';

// www.stackoverflow.com
echo preg_replace($regexp, '$1', 'http://www.stackoverflow.com/questions/ask');

// google.de
echo preg_replace($regexp, '$1', 'http://google.de/?q=hello');

// it works for the other input tests too ;-)

score 0 · Answer 7 · answered Apr 24 '15 at 19:27

0

Best way i think:

preg_match('/(http(|s)):\/\/(.*?)\//si',  'http://www.example.com/page/?bla=123#!@#$%^&*()_+', $output);
// $output[0] ------------>  https://www.example.com/

answered Apr 24 '15 at 19:27

T.Todua

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score 0 · Answer 8 · answered Aug 09 '10 at 17:03

0

Here's my quick and dirty solution.

http://([^/]+).*

I haven't tested it, but it should grab anything between the http:// and the first slash.

answered Aug 09 '10 at 17:03

haydenmuhl

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score 0 · Answer 9 · answered Aug 09 '10 at 17:05

0

if (preg_match('/http:\/\/([^\/]+)\//i', $target_string, $matches)) {
  $domain = $matches[1];
}

answered Aug 09 '10 at 17:05

theraccoonbear

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PHP REGEX: Get domain from URL

9 Answers9

Best way i think:

Linked

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