C# rounding with division

Question

This program calculates the amount of instances an event occurs within time. The issue is that when I'm getting decimal numbers the program does not round how I want it to, for example: if i divide 7/5 i get 1, is it possible to get 2? the 'double' answer yields: 1.4.

static void Main(string[] args) {
    var kim = 7/5 ;
    Console.WriteLine(kim);
    Console.ReadKey();
}

Any division I make I want it to round up.

For example: 7/5 = 1.4, but I want it to be 2; 5/2 = 2.5, but I want it to be 3, etc.

Jakub Lortz · Accepted Answer · 2015-12-24T00:23:40.113

9

7/5 is an integer division. It will always round down. You will need a double/decimal division and Math.Ceiling to round up:

Math.Ceiling(7.0 / 5.0);  // return 2.0

If your input values are ints, you will have to cast at least one of them to double

Math.Ceiling((double)7 / 5);

edited Dec 24 '15 at 00:23

answered Dec 24 '15 at 00:18

Jakub Lortz

14,616
3
25
39

my variables yield me 7 and 5, how do i convert them into decimals?, 7 --> 7.0? – Adan Dec 24 '15 at 00:20
@AdanRamirez cast them. I added it to the answer. – Jakub Lortz Dec 24 '15 at 00:24

Leejay Schmidt · Answer 2 · 2015-12-24T00:26:52.160

3

As Jakub said, you can use Math.Ceiling, or another option is to use the modulo. If the modulo is greater than 0, it means that there was some remainder and therefore you want to add 1, otherwise, you just add 0.

static void Main(string[] args)
{
    var kim = 7/5 + (7%5 > 0 ? 1 : 0);

    Console.WriteLine(kim);
    Console.ReadKey();
}

edited Dec 24 '15 at 00:26

answered Dec 24 '15 at 00:22

Leejay Schmidt

1,193
1
15
24

C# rounding with division

2 Answers2