Table not showing after insertion of Class

Question

I want to style the following mysqli output:

while($row = mysqli_fetch_array($result)) {
    $date = $row['name'];
    $comment = $row['id'];
    $amount = $row['icon'];
    echo 
"<tr><td style='width: 600px;'>".$date."</td></tr>
<tr><td style='width: 600px;'>".$comment."</td></tr>
<tr><td>".$amount."</td>
</tr>";
} 

echo "</table>";

I want to use for the <td style='width: 600px;'> a css class. If I use the following code, my mysql data disappears. Why?

<tr><td class="links">".$date."</td></tr>

This is not the complete code. This being in an `echo` and since you aren't really using `"` for the variable, you could change to `echo ''.$date.';'`. Also, that wouldn't just dissapear. It would probably give you an erro or warning. If you are using even notepadd++, you would be abe to see that the `"links"` part is actually closing the quote from the `echo` — FirstOne, Dec 24 '15 at 13:32

Tredged · Accepted Answer · 2015-12-24T13:49:16.053

2

What about, or am I saying something weird .. ?

<tr><td class='links'>".$date."</td></tr>

You need to escape the "", so it won't be interpreted as end of te echo. Use can also use \ to escape it. My way just solves it by switching the "" from links to ''.

edited Dec 24 '15 at 13:49

answered Dec 24 '15 at 13:32

Tredged

586
2
17

If he uses "" you can put the variables inside without chains. – Phiter Dec 24 '15 at 13:34
Like this right? @PhiterFernandes – Tredged Dec 24 '15 at 13:34
Actually ,like this: $date – Phiter Dec 24 '15 at 13:35
2

This is getting some votes, please insert more information than the code itself. Explain something... Get my comment, if you will – FirstOne Dec 24 '15 at 13:38
@FirstOne Thanks I will update ;-) – Tredged Dec 24 '15 at 13:39
Thats it. Thank you! – Hertus Dec 24 '15 at 13:40
@Hertus Please accept my answer in the left of the screen – Tredged Dec 24 '15 at 13:43

score 1 · Answer 2 · edited May 23 '17 at 12:04

Your code is wrong at

<tr><td class="links">".$date."</td></tr>

Should be

<tr><td class='links'>".$date."</td></tr>

If your echo is between quotes ",you must put the HTML stuff inside apostrophes '.

Also you won't need to chain the variables, since you are using quotes, so you can do it as follows:

<tr><td class='links'>$date</td></tr>

Here you can see a full text explaining the differences:

What is the difference between single-quoted and double-quoted strings in PHP?

Alaa M. Jaddou · Answer 3 · 2015-12-24T13:51:48.207

conver THIS

echo 
"<tr><td style='width: 600px;'>".$date."</td></tr>
<tr><td style='width: 600px;'>".$comment."</td></tr>
<tr><td>".$amount."</td>
</tr>";

if you start the echo statement with double quotation you need to use single in between like this

convert it TO

echo "<tr><td class='links'>".$date."</td></tr>"
."<tr><td class='links'>".$comment."</td></tr>"
."<tr><td>".$amount."</td>"
."</tr>";

OR you could right the html code out of your php code like this

?>
<tr><td class='links'><?php echo $date; ?></td></tr>
<tr><td class='links'><?php echo $comment; ?></td></tr>
<tr><td><?php echo $amount; ?></td></tr>
<?php

@FirstOne thanks for mention :) no problem :] – Alaa M. Jaddou Dec 24 '15 at 13:50 — Alaa M. Jaddou, Dec 24 '15 at 13:50

Table not showing after insertion of Class

3 Answers3