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I have tried using a variable as an input parameter to NSLocalizedString, but all I am getting back is the input parameter. What am I doing wrong? Is it possible to use a variable string value as an index for NSLocalized string?

For example, I have some strings that I want localized versions to be displayed. However, I would like to use a variable as a parameter to NSLocalizedString, instead of a constant string. Likewise, I would like to include formatting elements in the parameter for NSLocalizedString, so I would be able to retrieved a localized version of the string with the same formatting parameters. Can I do the following:

Case 1: Variable NSLocalizedstring:

NSString *varStr = @"Index1";
NSString *string1 = NSLocalizedString(varStr,@"");

Case 2: Formatted NSLocalizedString:

NSString *string1 = [NSString stringWithFormat:NSLocalizedString(@"This is an %@",@""),@"Apple"];

(Please note that the variable can contain anything, not just a fixed set of strings.)

Thanks!

futureelite7
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8 Answers8

127

If what you want is to return the localized version of "This is an Apple/Orange/whatever", you'd want:

NSString *localizedVersion = NSLocalizedString(([NSString stringWithFormat:@"This is an %@", @"Apple"]), nil);

(I.e., the nesting of NSLocalizedString() and [NSString stringWithFormat:] are reversed.)

If what you want is the format to be localized, but not the substituted-in value, do this:

NSString *finalString = [NSString stringWithFormat:NSLocalizedString(@"SomeFormat", nil), @"Apple"];

And in your Localizable.strings:

SomeFormat = "This is an %@";
Wevah
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  • Yeah, but the variable can contain anything, not just "apples" or "oranges". So I need to maintain flexibility. – futureelite7 Aug 10 '10 at 04:24
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    Let me append my answer just in case. – Wevah Aug 10 '10 at 09:28
  • Thank you very much; the appended answer is in fact what I was looking for -- and I hope you get an 'accept' checkbox soon. – RonLugge Nov 22 '12 at 03:13
  • You are not addressing the case 1: "Using variables and/or parameters with NSLocalizedString?". You can't do so and should use only const strings because localized strings should be translated before run time and string variable can be anything at runtime. – Sanich Nov 05 '18 at 10:15
24

I just want to add one very helpful definition which I use in many of my projects.

Inspired by androids possibility, I've added this function to my header prefix file:

#define NSLocalizedFormatString(fmt, ...) [NSString stringWithFormat:NSLocalizedString(fmt, nil), __VA_ARGS__]

This allows you to define a localized string like the following:

 "ExampleScreenAuthorizationDescriptionLbl"= "I authorize the payment of %@ to %@.";

and it can be used via:

self.labelAuthorizationText.text = NSLocalizedFormatString(@"ExampleScreenAuthorizationDescriptionLbl", self.formattedAmount, self.companyQualifier);
Alexander
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11

For swift :

let myString = String(format: NSLocalizedString("I authorize the payment of %d ", comment: ""), amount)
Xero
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6
extension String {
    public var localizedString: String {
        return NSLocalizedString(self, comment: "")
    }

    public func localizedString(with arguments: [CVarArg]) -> String {
        return String(format: localizedString, arguments: arguments)
    }
}

Localizable.string:

"Alarm:Popup:DismissOperation:DeviceMessage" = "\"%@\" will send position updates on a regular basis again.";
"Global:Text:Ok" = "OK";

Usage:

let message = "Alarm:Popup:DismissOperation:DeviceMessage".localizedString(with: [name])

and

let title = "Global:Text:Ok".localizedString
Michal Zaborowski
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4

It turns out that a missing target entry is to blame. Just checking that my current build target includes the Localizable.string file solved the problem!

futureelite7
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2

If you have more than one variable in your localized string can you use this solution:

In Localizable.strings

"winpopup" = "#name# wins a #type# and get #points# points(s)"; 

And use stringByReplacingOccurrencesOfString to insert the values

NSString *string = NSLocalizedString(@"winpopup", nil); //"#name# wins a #type# and get #points# points(s)"
NSString *foo = [string stringByReplacingOccurrencesOfString:@"#name#" withString:gameLayer.turn];
NSString *fooo = [foo stringByReplacingOccurrencesOfString:@"#type#" withString:winMode];
NSString *msg = [fooo stringByReplacingOccurrencesOfString:@"#points#" withString:[NSString stringWithFormat:@"%i", pkt]];
NSLog(@"%@", msg);
zeiteisen
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    this seems very complicated. you can just use numbered placeholders: `"exampleKey" = "%1$@ has bought %3$d apples and %2$d oranges."` `[NSString stringWithFormat:NSLocalizedString(@"exampleKey", nil), @"Markus", 4, 3]` This would output: `Markus has bought 3 apples and 4 oranges`. – denbec Aug 07 '12 at 14:06
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    And than go and explain these type of cryptographic strings to your translators around the world. – zeiteisen Aug 07 '12 at 14:55
  • %1 or %2 is what must be used. – Ricardo Apr 10 '14 at 11:13
0

Your ideas should work. But if you are getting back the input parameter, that means that the input parameter was not found as a key in your Localizable.strings file. Check the syntax and location of that file.

JWWalker
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0

This works for me:

NSMutableString *testMessage = [NSMutableString stringWithString:NSLocalizedString(@"Some localized text", @"")];
testMessage = [NSMutableString stringWithString:[testMessage stringByAppendingString:someStringVariable]];