I'm trying to make a shell script but I'm stuck.
This doesn't work and I don't know why.
a=( "1" "2" )
b=( "3" "4" )
c=( "$a" "$b" )
for d in "${c[@]}"; do
echo "${d[1]}"
done
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betseg
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In bash, array elements must be scalars, i.e., there's no multidimensional array in bash. – 4ae1e1 Dec 26 '15 at 11:31
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Do you know any way I can do something like this? – betseg Dec 26 '15 at 11:35
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ksh93 has multidimensional arrays. – 4ae1e1 Dec 26 '15 at 11:36
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Thanks, I'll give it a look. – betseg Dec 26 '15 at 11:38
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Have a look at this one: http://stackoverflow.com/questions/16487258/how-to-declare-2d-array-in-bash and this one too: http://stackoverflow.com/questions/11233825/multi-dimensional-arrays-in-bash – Jahid Dec 26 '15 at 13:47
1 Answers
2
With bash:
a=( "1" "2" )
b=( "3" "4" )
# concatenate array a and b to new array c
c=( "${a[@]}" "${b[@]}" )
for d in "${c[@]}"; do
echo "$d"
done
Output:
1 2 3 4
Cyrus
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