Intent tostart = new Intent(Intent.ACTION_VIEW);
tostart.setDataAndType(Uri.parse(video_path+".***"), "video/*");
startActivity(tostart);
Let's say I have a file path
/mnt/sdcard/video/my_birthday_moovie001
'my_birthday_moovie001' can be either .mkv, .mpg or .mkv. I've tried to add ".***" to the file path but I still can't open the file.
Well i read the comments you have stored your path in db without extensions there are many extensions that exists so android cant automatically pick the extension you have to create some way to detect extension.
following is a robust way that is best match in your case but not recommended in proper cases where extensions are known
public String chk_path(String filePath)
{
//create array of extensions
String[] ext=new String[]{".mkv",".mpg"}; //You can add more as you require
//Iterate through array and check your path which extension with your path exists
String path=null;
for(int i=0;i<ext.Length;i++)
{
File file = new File(filePath+ext[i]);
if(file.exists())
{
//if it exists then combine the extension
path=filePath+ext[i];
break;
}
}
return path;
}
now to play a song in your code
if(chk_path(video_path)!=null)
{
Intent tostart = new Intent(Intent.ACTION_VIEW);
tostart.setDataAndType(Uri.parse(video_path), "video/*");
startActivity(tostart);
}
else
//tell user that although the path in database but file on this path do not exists
Well as I put on comments
You could compare if the path matches with any filename(it doesn't contains the extension) and then if it does you got it.
You can simply do this :
Get the directory path
File extStore = Environment.getExternalStorageDirectory();
Set the file name my_birthday_moovie001 on my example I put unnamed but change it as your like
String NameOfFile = "unnamed";
Add the videos, I put it Downloads but you can change it
String PathWithFolder = extStore + "/Download/";
Create a method that lists all the files from your path
private List<String> getListFiles(File parentDir) {
ArrayList<String> inFiles = new ArrayList<String>();
File[] files = parentDir.listFiles();
for (File file : files) {
if (file.isDirectory()) {
inFiles.addAll(getListFiles(file));
} else {
String AbsolutePath = file.getAbsolutePath();
//Get the file name ex : unnamed.jpg
String nameofFile = AbsolutePath.substring(AbsolutePath.lastIndexOf("/") + 1, AbsolutePath.length());
//Remove the .jpg --> Output unnamed
String fileNameWithoutExtension = nameofFile.substring(0, nameofFile.lastIndexOf('.'));
//Add each file
inFiles.add(fileNameWithoutExtension);
}
}
return inFiles;
}
You got the names of the files doing this
List<String> files = getListFiles(new File(PathWithFolder));
Simply add a for that looks for a match of your file
for (int i = 0; i<=files.size()-1; i++){
if(PathWithFolder.equals(files.get(i))) {
Toast.makeText(MainActivity.this, "You got it!", Toast.LENGTH_SHORT).show();
}
else{
Toast.makeText(MainActivity.this, "You don't.", Toast.LENGTH_SHORT).show();
}
}
If you want to get the path as well and do what @Zain Ul Abidin proposed and compare it on getListFiles() method add this :
String fileExtension = nameofFile.substring(nameofFile.lastIndexOf("."));
Hope it helps.
From the other question :
Consider DirectoryScanner from Apache Ant:
DirectoryScanner scanner = new DirectoryScanner();
scanner.setIncludes(new String[]{"**/*.java"});
scanner.setBasedir("C:/Temp");
scanner.setCaseSensitive(false);
scanner.scan();
String[] files = scanner.getIncludedFiles();
You'll need to reference ant.jar (~ 1.3 MB for ant 1.7.1).
And then, run on files array and check if files[i].include(yourfile) yourfile= files[i]
You may try in this way , first getting the name of file and extension then finally compare and implement. like this :
Example file name is 04chamelon and extension is .png:
File f = new File("/mnt/storage/sdcard/Pictures/04chameleon");
File yourDir = new File("/mnt/storage/sdcard/Pictures");
nametwo = f.getName();
for (File fa : yourDir.listFiles()) {
if (fa.isFile())
fa.getName();
String path = fa.getName(); // getting name and extension
filextension = path.substring(path.lastIndexOf(".") + 1); // seperating extension
name1 = fa.getName();
int pos = name1.lastIndexOf(".");
if (pos > 0) {
name1 = name1.substring(0, pos);
}
}
if (name1.equals(nametwo)) {
Intent tostart = new Intent(Intent.ACTION_VIEW);
tostart.setDataAndType(Uri.parse(f + "." + filextension), "image/*");
//tostart.setDataAndType(Uri.parse(f + "." + filextension), "video/*");
startActivity(tostart);
}
With the latest ContentResolver, you can easily make this work using the contentResolver.getType(uri) function which detects the filetype.
private fun getIntentForFile(intent: Intent, filePath: String, context: Context): Intent {
val uri = FileProvider.getUriForFile(
context,
context.applicationContext.packageName + ".fileprovider",
File(filePath)
)
intent.putExtra(Intent.EXTRA_STREAM, uri)
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION)
intent.setDataAndType(uri, context.contentResolver.getType(uri))
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
return intent
}
