why double v2 = ((double)51/4)%2 is an illegal expression ni c++?

Question

I'm new to C++ and is trying to learn the concept of arithmetic operators. Could someone please tell me why statement 1 is legal while statement 2 is illegal?

Statement 1:

double v1 = (double)51/4;

Statement 2:

double v2 = ((double)51/4)%2;

Because finding the remainder is integer operation. – GingerPlusPlus Jan 02 '16 at 14:25 — GingerPlusPlus, Jan 02 '16 at 14:25

score 1 · Answer 1 · edited May 23 '17 at 11:52

1

In statement 2 you are using the modulus operator % on a double and an integer, however the modulus operator only works on integer-values.

More info here: Can't use modulus on doubles?

edited May 23 '17 at 11:52

Community

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answered Jan 02 '16 at 14:27

FrederikDS

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why double v2 = ((double)51/4)%2 is an illegal expression ni c++?

1 Answers1