Identify position of the items in xsl:for-each

Question

I have an Xml like below:

<data>
  <record id="1"/>
  <record id="2"/>
  <record id="3"/>
  <record id="4"/>
  <record id="5"/>
  <record id="6"/>
</data>

I want to print this xml as

**TRIM("1"-"2"-"3"-"4"-"5"-"6")**

I am using simple xsl like below

<xsl:for-each select="descendant-or-self::*/record">
    <xsl:text>TRIM("</xsl:text>
    <xsl:value-of select="@id"/>
    <xsl:text>"-"</xsl:text>
    <xsl:text>)</xsl:text>
</xsl:for-each>

the first item only requires <xsl:text>TRIM("</xsl:text> and last item requires <xsl:text>)</xsl:text>. How to achieve this in order to get the result TRIM("1"-"2"-"3"-"4"-"5"-"6")

Possible duplicate of [XSLT concat string, remove last comma](http://stackoverflow.com/questions/798269/xslt-concat-string-remove-last-comma) — , Jan 06 '16 at 03:51

Gururaj Venkatakrishnarao · Answer 1 · 2016-01-06T04:50:39.350

0

I got an answer. it is

<xsl:for-each select="descendant-or-self::*/record">
    <xsl:if test="position() = 1">
        <xsl:text>TRIM("</xsl:text>
    </xsl:if>
    <xsl:value-of select="@id"/>
    <xsl:text>"-"</xsl:text>
    <xsl:if test="position() = last()">
        <xsl:text>)</xsl:text>
    </xsl:if>
</xsl:for-each>

edited Jan 06 '16 at 04:50

answered Jan 06 '16 at 03:49

Gururaj Venkatakrishnarao

15
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Identify position of the items in xsl:for-each

1 Answers1