How do I pass multiple arguments into a filter?
Trying the following
mylist = $filter('filter')(array, {'field': 'param1'} || {'field': 'param2'} );
but this only uses the first filter param rather than both.
What is the correct syntax?
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user2085143
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Duplicate of http://stackoverflow.com/questions/16227325/how-do-i-call-an-angular-js-filter-with-multiple-arguments – Eria Jan 06 '16 at 11:22
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Are you trying to filter array where `field == param1 || field == param2` ? – PrinceG Jan 06 '16 at 11:32
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Here is a possible duplicate http://stackoverflow.com/questions/15868248/how-to-filter-multiple-values-or-operation-in-angularjs – PrinceG Jan 06 '16 at 11:35
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@prince yes I am. Thought it would be possible without writing a custom filter. – user2085143 Jan 06 '16 at 12:00
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You would likely have to customize this, but you can pass a function $filter('filter')(array, function(v,i) { return v.field == 'param1' || v.field == 'param2'; } ) https://docs.angularjs.org/api/ng/filter/filter – George Houpis Jan 06 '16 at 16:08