A simpler solution, building on Yasir Al-Agl's answer:
function sortList()
{
var lb = document.getElementById('mylist');
arr = new Array();
for(i = 0; i < lb.length; i++) {
arr[i] = lb.options[i];
}
arr.sort(function(a,b) {
return (a.text > b.text)? 1 : ((a.text < b.text)? -1 : 0);
}); // or use localeCompare() if you prefer
for(i = 0; i < lb.length; i++) {
lb.options[i] = arr[i];
}
}
In short, you need only one Array, the elements of which are simply references to the original "options" Objects. The sort() function also has the freedom to choose which option property to sort on (ie, the text property, the value property, etc).
Don't forget, however, that the "selectedIndex" property of the "select" control may no longer be correct after the sort.