Can we get the wifi name in the ios simulator

Asked Jan 08 '16 at 10:48

Active Jan 08 '16 at 11:11

Viewed 1,479 times

I can get the wifi name from a real device, but in the simulator it is not giving any value. Is it possible to get the wifi name in the simulator? Is there any options to get the default wifi name like location services?

Below is my code to get the wifi name on the real device

- (NSDictionary *)fetchSSIDInfo
{
    NSArray *interfaceNames = CFBridgingRelease(CNCopySupportedInterfaces());
    NSLog(@"%s: Supported interfaces: %@", __func__, interfaceNames);

    NSDictionary *SSIDInfo;
    for (NSString *interfaceName in interfaceNames) {
        SSIDInfo = CFBridgingRelease(
                                     CNCopyCurrentNetworkInfo((__bridge CFStringRef)interfaceName));
        NSLog(@"%s: %@ => %@", __func__, interfaceName, SSIDInfo);

        BOOL isNotEmpty = (SSIDInfo.count > 0);
        if (isNotEmpty) {
            break;
        }
    }
    return SSIDInfo;
}

edited Jan 08 '16 at 11:11

Johnykutty

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asked Jan 08 '16 at 10:48

Test iOS

No, you won't get SSID Info when it is with simulator. – Uma Madhavi Jan 08 '16 at 10:54
is there is any options to give a default wifi name & get that name,like the location service ,in the location we can set some manual location like that any option avilable? – Test iOS Jan 08 '16 at 10:57
I guess no because in simulator we don't have any (settings) wifi kind. – Uma Madhavi Jan 08 '16 at 11:00
in simulator setting-> Developer->wifi is avilable – Test iOS Jan 08 '16 at 11:03
What do you get if you use `NetworkExtension` instead? http://stackoverflow.com/a/31590787/78496 – chedabob Jan 08 '16 at 11:11
@chedabob ok thanks how can i get list of wifi available without using private APIs – Test iOS Jan 08 '16 at 12:11
You don't need to use private API for your method or the one I've linked – chedabob Jan 08 '16 at 14:16
this one i'm getting only the connected connected wifi only – Test iOS Jan 11 '16 at 04:50

Can we get the wifi name in the ios simulator

0 Answers0