Dynamic binding with constructor

Question

I am a bit confused with the binding type of a constructor. Why is calling

Canvas c = new Circle(); not dynamic binding?

Thank you!

see here about static binding and dynamic binding - http://beginnersbook.com/2013/04/java-static-dynamic-binding/ — Razib, Jan 08 '16 at 18:34
Because it is absolutely and explicitly clear *at compile time* that a certain constructor of class Circle is being called. — laune, Jan 08 '16 at 18:34
http://javaconceptoftheday.com/static-binding-and-dynamic-binding-in-java/ — ryekayo, Jan 08 '16 at 18:35

score 0 · Accepted Answer · answered Jan 08 '16 at 19:13

It is static binding as it is done during compile time.

If class Circle has a method that overrides a method from Canvas and you call that method like the following, then it is called dynamic binding.

//if you override some method in the child class that is Circle 
c.someMethod() //example of dynamic binding

You can read static vs dynamic for more.

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