How to check if result is integer in Python?

Question

I have simple task to count number, for example:

a = 7
b = 9
result = 0

for _ in (0:100):
     result = a / b
     b += 1

How I can stop the for loop when result is an integer?

Checking if method is_integer() wasn't meet my expectations.

I have to use Python 2.6

I hope yoiu know the above code is not even syntactically valid - the for statement in Python always iterate through sequences - if you want a numeric for loop, the usueal thing to do is to use the built-in `range` function - thus: `for _ in range(0, 100):` is a valid way to do it. — jsbueno, Jan 09 '16 at 11:07
In Python 2.x, the normal division is constrained to integer results by default - so you probably have problems very soon. You can, on the first line of your program, write the statement `from __future__ import division` so that the result of an integer division can be a float. — jsbueno, Jan 09 '16 at 11:09
I rolled back your latest edit. On Stack Overflow, you mark a problem as resolved by accepting an answer. If none of the answers is completely satisfying, feel free to post an answer of your own. — tripleee, Jan 09 '16 at 12:49

score 3 · Accepted Answer · edited May 23 '17 at 11:53

3

Use % 1. Modular arithmetic returns the remainder, so if you try to divide by 1 and the remainder is 0, it must be an integer.

if result % 1 == 0:
    print "result is an integer!"

OR use the method mentioned in this post or this post:

if result.is_integer():

As mentioned in the comments, you can use:

while result % 1 != 0:

to make the loop repeat until you get an integer.

edited May 23 '17 at 11:53

Community

answered Jan 09 '16 at 11:05

Arc676

score 2 · Answer 2 · answered Jan 09 '16 at 11:14

2

If you're using python 2.6 you could use:

isinstance(result, (int, long))

to check if your result is an integer.

answered Jan 09 '16 at 11:14

trantimus

score 1 · Answer 3 · answered Jan 09 '16 at 11:08

1

You could use the type method:

if type(a/b) == int:
    break

You could also use the while loop approach as suggested by other answers:

   while type(a/b) != int:
       # your code

answered Jan 09 '16 at 11:08

deborah-digges

3 Answers3