void operator overloading c++

Question

#include <iostream>
using namespace std;

class Circle{
public:
 Circle(){ cout<<"im a circle\n"; }
 void operator+(){ cout<<"im a + operator\n"; }
};

int main()
{
  Circle();
  Circle();
  + 
  Circle();
}

output

"im a circle"

"im a circle"

"im a circle"

"im a + operator"

i want to receive output with this order

"im a circle"

"im a circle"

"im a + operator"

"im a circle"

I want as third output im a + operator. How can I fix this code so the output is in this specific order?

Your code shouldn't even compile because there is no `operator()` defined. Please read http://stackoverflow.com/help/mcve — Praetorian, Jan 11 '16 at 20:57
@therealp A `Circle` instance needs to be constructed first before you can invoke `operator+` on it. Perhaps you're looking for `Circle a, b; +a; Circle c;` or `Circle(); +Circle(); Circle();` — Praetorian, Jan 11 '16 at 21:07

score 1 · Answer 1 · answered Jan 11 '16 at 21:12

1

To get the output wanted just write

int main()
{
  Circle a;
  Circle b;
  +a; 
  Circle c;
}

See a working demo.

answered Jan 11 '16 at 21:12

πάντα ῥεῖ

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thanks! but is necessary to give only the "+" operator without a; – Lk2 Jan 11 '16 at 21:22
@therealp That's not a valid c++ expression, thus you are lost. Why is this needed actually? You can't call an operator without a concrete instance. – πάντα ῥεῖ Jan 11 '16 at 21:24
1

@therealp Oh, I'm surprised now. May be you could add another answer that shows how you actually fixed your code achieving the requirement stated in your 1st comment? I'm just curious. – πάντα ῥεῖ Jan 11 '16 at 21:32

void operator overloading c++

1 Answers1