Can't call function Python

Question

Here is my code that calls the __init__ of Game_Events class:

class Game_Events(object):
    def __init__(self, DoSetup):
        if DoSetup == "yes":
            print "Done"

GE = Game_Events()
GE.__init__("no")

But when ever I run the code I get:

TypeError: __init__() takes exactly 2 arguments (1 given)

How can I fix this?

`GE = Game_Events("no")`, you might also be better of giving DoSetup a default value `DoSetup=False` — Padraic Cunningham, Jan 12 '16 at 13:19
This may provide you with more information on init: http://stackoverflow.com/questions/8609153/why-do-we-use-init-in-python-classes — Panda, Jan 12 '16 at 13:46

Martijn Pieters · Answer 1 · 2016-01-12T13:20:54.393

4

Game_Events.__init__() is called for you, you don't call it directly. It is called when you create an instance:

Game_Events()  # calls Game_Events.__init__(newly_created_instance)

Because you didn't pass in an argument to that call, things break. Pass in 'no' to that call:

GE = Game_Events('no')  # calls Game_Events.__init__(newly_created_instance, 'no')

edited Jan 12 '16 at 13:20

answered Jan 12 '16 at 13:20

Martijn Pieters

1,048,767
296
4,058
3,343

score 0 · Answer 2 · answered Jan 12 '16 at 13:21

init functions are called while creating an instance for that class only.

Try this:

class Game_Events(object):
    def __init__(self, DoSetup):
        if DoSetup == "yes":
            print "Done"

GE = Game_Events("no")

GE = Game_Events("yes") # output will be yes

Can't call function Python

2 Answers2