Python3 print in hex representation

Question

I can find lot's of threads that tell me how to convert values to and from hex. I do not want to convert anything. Rather I want to print the bytes I already have in hex representation, e.g.

byteval = '\x60'.encode('ASCII')
print(byteval)  # b'\x60'

Instead when I do this I get:

byteval = '\x60'.encode('ASCII')
print(byteval)  # b'`'

Because ` is the ASCII character that my byte corresponds to.

To clarify: type(byteval) is bytes, not string.

Is this work for you http://stackoverflow.com/questions/2340319/python-3-1-1-string-to-hex/2340358#2340358? — Ivan Velichko, Jan 12 '16 at 14:42
If you want `\x60` to appear, then you *want to* convert your string. — Andrea Corbellini, Jan 12 '16 at 14:44
My input is of type Bytes(), not a string, hence I do not want to convert it. the encoding of '\x60' using ASCII is to have a self contained example. — Adriaan Rol, Jan 12 '16 at 15:52
I don't understand why does it matter to you if its printed "\x60" or "`" ? in both cases doing ord(byteval) will return 96 — Ramast, Jan 12 '16 at 16:00

score 5 · Accepted Answer · answered Jan 12 '16 at 16:39

5

>>> print("b'" + ''.join('\\x{:02x}'.format(x) for x in byteval) + "'")
b'\x60'

answered Jan 12 '16 at 16:39

Robᵩ

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score 1 · Answer 2 · answered Sep 22 '21 at 12:32

See this:

hexify = lambda s: [hex(ord(i)) for i in list(str(s))]

And

print(hexify("abcde"))
# ['0x61', '0x62', '0x63', '0x64', '0x65']

Another example:

byteval='\x60'.encode('ASCII')
hexify = lambda s: [hex(ord(i)) for i in list(str(s))]
print(hexify(byteval))
# ['0x62', '0x27', '0x60', '0x27']

Taken from https://helloacm.com/one-line-python-lambda-function-to-hexify-a-string-data-converting-ascii-code-to-hexadecimal/

Python3 print in hex representation

2 Answers2