Modifiying variables that only differ in the index

Question

I was programming right now and I wanted to modify the value of ten variables that shared their name but had a different index at the end. For example:

    int number1
    int number2
    int number3
    int number4
    ...

If I want to put the same value in all the variables, for example initialize them at 0, Is there any way to do this with a loop in which I only have to modify the index?

Something like this:

    for(int i=0;i<=10;i++) {
       number"i" = 0; }

Probably it is a silly question, but I can't find the solution. Thank you very much :)

Oh, I didn't think about using an Array. That makes sense. It was a very stupid question, sorry :( — Gonzalo De la Cruz, Jan 16 '16 at 15:59

score 1 · Answer 1 · answered Jan 16 '16 at 15:59

As mentioned in the comment, go for an array.

From the loop given in your question, it seems as if you want 10 numbers. In that case something like

int[] arNum = new int[10];

should declare the array.

To initialize the array with all 0, try

for (int i = 0; i < 10; i++)
    arNum[i] = 0;

Note: Array indexes always start at 0.

score 0 · Answer 2 · edited May 23 '17 at 11:59

0

Just use an array:

int[] arr = new int[10];

To be clear:

Each class variable, instance variable, or array component is initialized with a default value when it is created (§15.9, §15.10) [...] For type int, the default value is zero, that is, 0.

Taken from here. You might also want to take a look here.

edited May 23 '17 at 11:59

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answered Jan 16 '16 at 16:03

pzaenger

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Modifiying variables that only differ in the index

2 Answers2